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How to use the number 2,0,1,8 to make 51?

You can use any operation except for multiple factorials and you can concatenate numbers, ex.2,0=>20

You can take the square root of a number without a two, but if you want to take the cubic root you will need a three.

JMP
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8 Answers8

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I think this is valid by your rules :

$ \frac{\sqrt{\sqrt{.1^{-8}}}}{2} + 0! $

$= \frac{100}{2} + 1$

$= 51$

Keelhaul
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3

$\lceil{(8.1-0!)^2}\rceil=51$

Explanation:

$\lceil$ $\rceil$ rounds above. ;

$(8.1-0!)^2=(8.1-1)^2=7.1^2=50.41$ ;

$\lceil50.41\rceil=51$

Lolgast
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Evargalo
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  • I've changed your commas to dots - while commas seem to be the convention in more countries (see wikipedia ), the dot is standard for English speaking countries. Also, the rendering for commas is a bit weird - it inserts spaces, causing the numbers to appear as separate numbers which may leave readers confused at first (including me) – Lolgast Jan 09 '18 at 13:35
  • @Lolgast You can use {,} to render a decimal comma: $8{,}1$. – yo' Jan 09 '18 at 14:24
  • Ah, good to know! Though I'm still of the opinion that a dot should be used... That's also the convention my (internationally oriented) university uses for technical, English papers, even though being based in a comma-based country (the Netherlands). – Lolgast Jan 09 '18 at 14:26
2

Finally got it

Concatenate the following 2 results
(8-2-1)(0!)

stack reader
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2

How is this-

(18-0!) * T2 = (18-1) * 3 = 17 * 3 = 51

Here, T is- triangular number

Minhas Kamal
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102/(cube root of 8) = 102/2 = 51

Mehul Shah
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0

I feel like I'm not too far away:

51 = (2^8-1)/5, but I can't make the /5, a *.2 would also solve it
or, 51 = (8^3-2)*.1, but I can't make the 3. It feels so close, and yet so far...

Florian Bourse
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0

$51 = ((2 + 0!)!)!! + \sqrt{(1 + 8)}$

$= 6!! + 3 = 2 * 4 * 6 + 3 = 48 + 3$

!! is Double factorial.

Credit also goes to @KaiNoack for his comment on my question and to EmNero from the German math forum who used double factorials to get 48.

EDIT: I've just noticed I misread the comment by @ReallyDesperatePerson. I thought it said you can use double factorials, but it says you can't use them. Sorry! I hope I can leave the answer because it is mathematically correct, but it is against the challenge rules so please don't upvote it.

fitch496
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  • Multiple factorial is prohibited. – athin Jan 09 '18 at 10:00
  • Oh. I've just noticed I misread the comment by @ReallyDesperatePerson. I thought it said you can use double factorials, but it says you can't use them. Sorry! – fitch496 Jan 09 '18 at 10:04
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solution : √(2801-200) = √2601 = 51

J. Daniel
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