Four numbers are available: $1$, $3$, $4$ and $6$. Every number must be used once and only once with (some of) the operations $+$, $-$, $\times$, $\div$ to form the number $24$.
It's from the book "Art of Exploitation", 2nd edition. Give it a try!
Four numbers are available: $1$, $3$, $4$ and $6$. Every number must be used once and only once with (some of) the operations $+$, $-$, $\times$, $\div$ to form the number $24$.
It's from the book "Art of Exploitation", 2nd edition. Give it a try!
An answer to this problem is:
$6 \div (1 - \frac34)$
Another possible answer could be...
$(14-6) \times 3 = 24$
Bit of an off the wall answer
(6-4)(3+1) forms 24 if you calculate the values within the brackets, and leave the results as they are
Not mathematically correct at all I know, it's an answer that loosely fits the wording of the puzzle
Answer could also b:
$6 \times 4 \times 1^3$
** and as * is allowed, and there is no specify notation
– user902383
Mar 08 '16 at 13:05