$$ 4\sum_{n=0}^{\infty}\frac{(-1)^n}{2n+1}\\ (-\infty,...,-1,0,1,...,\infty)\times(-\infty,...,-1,0,1,...,\infty)\\ \forall\begin{bmatrix}{-1}&{0}\\ {0}&{-1} \end{bmatrix} $$
Asked
Active
Viewed 4,662 times
53
-
1This is beautiful! I think I've half-realized the solution, though there's a piece that's giving me a hard time! – leoll2 Jun 02 '15 at 11:48
-
nice one. i think i've got everything except for the matrix. that's the part giving me a headache – Jun 02 '15 at 12:15
-
This definitely involves some circular reasoning, but I also haven't figured out the right way to read the matrix. – Glen O Jun 02 '15 at 12:19
-
Try to identify the Matrix. – Masclins Jun 02 '15 at 12:24
-
2Really , nice one! – Saurabh Prajapati Jun 02 '15 at 12:48
-
3Perfect puzzle! +1 – BmyGuest Jun 02 '15 at 20:01
1 Answers
49
The first line is
equal to Pi.
The second line is
the integers, Z, multiplied by itself, making Z2.
The third line is
multiplying some matrix ∀ by the negative identity matrix, negating its value. The letter ∀ negated is A.
All together,
Pi + Z2 + A = Pizza.
Kevin
- 6,449
- 1
- 31
- 30
-
9Wow, the last line was very lateral-thinking! I really couldn't realize the meaning of "for every point reflection" – leoll2 Jun 02 '15 at 12:27
-
2When I thought about using the Matrix for making $\forall$ become A, I thought about the 180º rotation Matrix. – Masclins Jun 02 '15 at 12:28
-
1Ah! Rotation. I figured there was a more specific term than "negating". I should have been thinking more geometrically. – Kevin Jun 02 '15 at 12:43
-
1Surely if you're applying a rotation matrix to $\forall$, the matrix ought to be placed before the $\forall$. – David Zhang Jun 02 '15 at 22:07
-
4