24

Tile a square with twenty congruent right-angled triangles. For each triangle, one leg is of length 1 and the other leg is of length 2.

Will Octagon Gibson
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3 Answers3

28

Note first that

the area of the square is 20 times the area of the triangle, namely 20, so the side length is $2\sqrt5$.

That's

twice the hypotenuse of the triangle

which immediately suggests the overall shape of the thing. With apologies for the horrific ASCII art:

.   .   .   .   .   .   .
            ..''|:
.   .   ..''.___. : .   .
    ..''|       |  :
..''.___.___.___.___:   .
 :  |       |       |:
. : .___.___.___.___. : .
   :|       |       |  :
.   :___.___.___.___.___:   .   .
     :  |       |   ..''`
.   . : .___.___..''.   .   .   .
       :|   ..''
.   .   :.''.   .   .   .   .   .

where

each of those 2x1 rectangles is of course divided into two triangles by one of its diagonals.

Here, have some slightly less horrific not-ASCII not-art:

enter image description here

Gareth McCaughan
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24

May I offer a more aesthetic tiling?

enter image description here

Daniel Mathias
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17

Using the solution of this classic puzzle, "If the dotted lines connect the midpoint of each edge with a vertex, find the fraction of the area of the yellow square to the large red one":

classic puzzle

namely,

1/5 i.e. the same as each of the 4 red triangles.

Each red triangle and the yellow square can be divided into 4 of the triangles given in the question, resulting in this neat solution:

solution

Gnubie
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