What is the last integer in this sequence?

Question

Here are the first several entries in a finite sequence of integers.

$$ 31, 45, 71, 89, 91, 94, 111, 112, 118, 121, 126, 131, $$ $$ 134, 135, 139, 143, 144, 145, 148, 158, 161, 189, 193, 194, \dots $$

Your challenge is to identify the sequence, and give its final entry.

________
_{Let me (again) state for the record that I know What (Not) To Do in a Number Sequence Puzzle. There should be enough information provided here to make this sequence puzzle uniquely solvable.}

It is a monotone increasing sequence of integers and thus it must converge to infinity! — Yanko, Mar 18 '23 at 19:49

score 22 · Accepted Answer · answered Mar 18 '23 at 01:47

The final entry is

2325

Reasoning:

Converting A=1,Z=26 for the first few we get:
CA 31
DE 45
GA 71
HI 89
IA 91
ID 94
These are US state abbreviations, so 111 must be AK.
They are sorted in ascending numerical order, so running all 50 states through this method, the largest and last ends up as WY (Wyoming) = 2325.
(We know it's 50 because DC, Guam, etc. are excluded from the given list.)

An aside:

The 'hint' here (that I didn't notice until I wrote this up) is "let me state"...

Let me state that this answer is 100% correct. :) – Rubio Mar 18 '23 at 22:21 — Rubio, Mar 18 '23 at 22:21

What is the last integer in this sequence?

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