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So from a couple other puzzles, you might remember that I'm a professor of Awesomeness at the Ad Hoc University! This time, I've given my students some numbers and their scorez. They need to tell me how I scored them!

Here we are:

197 = 26 + 592 = 618

1 = 0 + 1 = 1

1337 = 44 + 8584 = 8628

43770 = 163 + 83104 = 83267

7 = 16 + 52 = 68

2020 = 63 + 2752 = 2815

Hint 1:

You remember how I said "Note: all the information of the puzzle is in the blockquote; nothing outside the blockquote is relevant!" in my Scoring a grid puzzle? Yeah, well I didn't say that here!

Voldemort's Wrath
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3 Answers3

5

First off

The 'strange' letters in the introduction are:
A oc t z ll
These are either written in italics or in z's case slang in 'scorez'

aoctzll is an anagram for collatz (and also lolcatz)

This of course hints towards

The collatz conjecture, a famous unsolved problem in mathematics. Simply put, do the following to a positive integer until it's equal to 1
- If it's even, divide by 2
- If it's odd, multiply by 3 and add 1

Now let's note:

If we take the leftmost number $n$ of each line, apply the collatz procedure to it, count the number of steps $s$ it takes to reach 1: The next number in the line is always equal to $s$.
And the next, third, number is the highest value the procedure reaches in between. Adding those two together is the final score.

Lukas Rotter
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4

Starting with the answer by @Lukas Rotter:

I had notice A oc t ll
but I missed the z. I think my brain just elides spelling errors in public forums.

And @Lukas Rotter is correct, it is based on the Collatz conjecture.

I looked at it more deeply, and found, that in A = B + C = D

A is the starting number.
B is the number of iterations to reach 1.
C is the highest number reached.
D is B + C

Thus, for example, we would see:

3 = 7 + 16 = 23

Because the sequence is:
3, 10, 5, 16, 8, 4, 2, 1
7 steps, max of 16

David G.
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I am going to give it a try, hoping that my answers are correct..

$197=9+9+7+1=26$
$97*(7-1)+9+1=592$
$26+592=618$

$1=1*0=0$
$1^1=1$
$0+1=1$

$1337= (7^2+1)-(3+3)=44$
$(7-1)*1337+337+133+(33*3-7)=8584$
$44+8584=8628$

$43770=(7*7*3)+(7+7+3)-3^0=163$
$3*377*70+(4377-437)-(7+3-4)=83104$
$163+83104=83267$

$2020=20+20+20+2^0+(2+0)=63$
$(20*20*7)-(20+20+7+2^0)=2752$
$63+2752=2815$

Vassilis Parassidis
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