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See if you can solve this math-problem:

$$ \begin{bmatrix} 1&+&1&=&0\\ 2&+&8&=&2\\ 2&+&2&=&0\\ 9&+&8&=&3\\ 3&+&4&=&0\\ 6&+&9&=&2\\ 0&+&2&=&1\\ 9&+&3&=&? \end{bmatrix} $$

Best of Luck!

Ps: Here is the link without brakets and here is one without latex

math scat
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  • If you can't see the $\LaTeX$(latex) commands It is here in normal symbols: – math scat Jul 23 '20 at 11:20
  • 1+1=0 2+8=2 2+2=0 9+8=3 3+4=0 6+9=2 0+2=1 9+3=? – math scat Jul 23 '20 at 11:22
  • $1+1=0\2+8=2\2+2=0\9+8=3\3+4=0\6+9=2\0+2=1\9+3=?$ – math scat Jul 23 '20 at 11:24
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    I'm sure I've seen this idea on this site before but can't find the dup. – hexomino Jul 23 '20 at 11:35
  • @hexomino I thought exactly the same, and looked for a good 10 minutes before posting! :) Always tricky when the concept you need to search for is hidden behind a spoiler block rather than present in the original question, as these don't get picked up by Search... – Stiv Jul 23 '20 at 11:36
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    @hexomino This is the closest I've been able to find - quite a different question using the same general concept at its core. Not convinced it's close enough for a dup... – Stiv Jul 23 '20 at 11:47
  • @Stiv You've done better than I have, I'd forgotten about this one. I feel like the sum version has come up before too, though. It's no biggie really, it has to be expected that similar ideas will crop up multiple times, well done on answering. – hexomino Jul 23 '20 at 11:55
  • @hexomino This is the one you're thinking of (one of the most common dupe targets on PSE), but it doesn't involve sums. Close enough for a dupe? I could go either way really ... – Rand al'Thor Jul 24 '20 at 05:58
  • Does this answer your question? Determine the algorithm (I feel like this is dupey enough because both questions rely on extracting the number on the right in the same way from some numbers on the left, whether or not there's a $+$ sign in the middle). – Rand al'Thor Jul 24 '20 at 05:58

2 Answers2

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The answer is:

$$9+3=1$$
In each case, what's being added together here is the number of 'closed counters' (i.e. the 'holes' in the numbers) when the numbers are written out on a standard 7-segment calculator display1. The digit 9 has one closed counter, while 3 has zero. The sum is thus 1.

1 This should rule out any queries surrounding the number '4', which can be considered to have 1 or 0 closed counters in different typefaces.

Stiv
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2

My Math logic


 Since 1+1=0 and 2+2=0, I assume that adding the same number gives me zero.
 We also have 0+2=1, meaning that 0+x=1
 9+3 = ?, but we know that 9+8=3, so we can reach this form
 9+3 = ?
 9+(9+8) = ?
 9+9+8 = 0+8 = 1
 Answer 1
Ny'alotha Slaanesh
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