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The speed of molecules in the atmosphere vary, and can exceed the escape velocity of the earth, $11\:\mathrm{km\:s^{-1}}$

If this happens, and has been happening for millions of years, how hasn't all of the gas escaped? Is there gas re-entering?

Is the process so slow the effects are negligible?

Qmechanic
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Tobi
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    The velocities of molecules are boltzman distributed around about $250\frac{m}{s}$ with small variance, so there's actually very few "escaping" molecules. – Nimrod Morag Nov 20 '16 at 15:49
  • So it's the latter? Is the process so slow the affects are negligible? – Tobi Nov 20 '16 at 15:58
  • see http://earthsky.org/earth/what-keeps-earths-atmosphere-on-earth – sammy gerbil Nov 20 '16 at 16:41
  • Note that every alpha decay, anywhere throughout the mass of the earth, adds a helium atom to the earth's helium balance... – DJohnM Nov 20 '16 at 17:22
  • I hate how my question was changed to have an overly complex title... – Tobi Nov 20 '16 at 17:26
  • @Tobi You can roll back the edits if you feel they're not necessary. – HDE 226868 Nov 20 '16 at 17:27
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    @Tobi You can indeed rollback the edits, but in general longer and more descriptive titles are better. This one, in particular, is pretty close to being clickbait, which we very much try to avoid here. In any case, there's no need to undo the other fixes. (In particular, note that "affect" is not a noun.) – Emilio Pisanty Nov 20 '16 at 17:38
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    I fail to see how editing is censorship – Kyle Kanos Nov 20 '16 at 18:31
  • Also: closely related: http://physics.stackexchange.com/q/34895/. Also related to: http://physics.stackexchange.com/q/201192/ and links therein – Kyle Kanos Nov 20 '16 at 18:52

2 Answers2

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There are two main groups of processes leading to atmospheric escape: thermal and non-thermal processes.

The first group includes Jeans escape, where particles with high thermal energies (and thus high kinetic energies) manage to reach speeds in the upper atmosphere greater than escape velocity. The equation for the Jeans flux for particles of mass $m$ is $$\phi_J(m)\propto n_c\sqrt{\frac{2kT}{m}}\left(1+\frac{GMm}{kTr}\right)\exp\left(-\frac{GMm}{kTr}\right)$$ to within an order of magnitude or so. This shows that the flux strongly favors lower-mass molecules, including hydrogen and helium (possibly in molecular form).

Non-thermal processes include collisions and interactions with charged particles, possibly from the solar wind. Again, lower-mass particles are favored to take part in these interactions. This may be mitigated by the presence of a magnetosphere, which can shield particles. Impact erosion is another possibility, and may have been important early in the Solar System when large impacts were frequent.

All of this means that the Earth and the other terrestrial planets should indeed have lost some of their atmospheres now . . . but mainly the hydrogen and helium components of the original envelope.

Is the process so slow the effects are negligible?

For more massive molecules, yes. The proportionality constant for Jeans flux is $\frac{B}{2\sqrt{\pi}}$ for some efficiency $B$, which we can take to be $1$, for a worst-case scenario. We'll also assume a mean temperature of $\sim1000\text{ K}$. We therefore find $$\sqrt{\frac{2kT}{m}}\sim770\text{ m/s},\quad\text{N}_2$$ $$\sqrt{\frac{2kT}{m}}\sim720\text{ m/s},\quad\text{O}_2$$ Placing the lower edge of the exosphere at about $500$ kilometers above Earth's surface ($r=R_e+500,000\text{ m}$) means that $$\frac{GMm}{kTr}\sim196,\quad\text{N}_2$$ $$\frac{GMm}{kTr}\sim225,\quad\text{O}_2$$ Substituting in, we get $$\phi_J\sim3.23\times10^{-81}\times n_{\text{N}_2}\text{ m}^{-2}\text{ s}^{-1},\quad\text{ N}_2$$ $$\phi_J\sim8.82\times10^{-94}\times n_{\text{O}_2}\text{ m}^{-2}\text{ s}^{-1},\quad\text{ O}_2$$ Even when multiplied by the area of a sphere with radius $r$, this is many orders of magnitude too low. Jeans escape is not at all important.

For heavier molecules, dissociation and non-thermal escape is a more important cause of atmosphere loss. It seems like the consensus for oxygen loss is that $\sim10^{24}$ molecules of $\text{O}+$ are lost from Earth every second, most around the polar regions, though some oxygen is again returned to Earth's atmosphere (there is a net outflow). This might seem like a lot, and it is, compared to the results from Jeans escape, but it turns out that this is about the amount of molecules in one cubic meter of air.

The main source of this atomic oxygen is through dissociative recombination: $$\text{O}_2^++e^-\to\text{O}+\text{O}+\text{energy}$$ which can create "hot" oxygen. I'm currently unaware of similar processes involving $\text{N}_2$ that occur at any significant rate on Earth, although the same reaction for nitrogen does apparently occur on Mars.

References

HDE 226868
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  • Can you clarify your last point with a numerical estimate of the rate of $\rm O_2$ and $\rm N_2$ depletion as compared to the current amounts in the atmosphere? – Emilio Pisanty Nov 20 '16 at 16:54
  • We also have a certain amount of material falling to the Earth from space. http://www.popsci.com/60-tons-cosmic-dust-fall-earth-every-day – David Elm Nov 20 '16 at 16:55
  • @EmilioPisanty I have estimates of Jeans escape for $\text{O}_2$ and $\text{N}_2$ up. I can get you information on dissociation soon. – HDE 226868 Nov 20 '16 at 17:26
  • @HDE that's interesting - and yeah, if there's an $m$ inside the exponential, then the dissociation channels are likely to be nontrivial. – Emilio Pisanty Nov 20 '16 at 17:29
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    Since the exponential term is so important, it's also worth explaining the physical reasons why it's there. With the numbers you give this really is the heart of the calculation. If I understand it correctly, it's because you need to account for the potential energy in the thermal velocity distribution, right? If so, then that's a good indication of where you need to take $r$ - at the lowest place where the mean free path is just too long to stop a given escape-velocity molecule. – Emilio Pisanty Nov 20 '16 at 17:36
  • the Earth is losing 1 m^3 per second of oxygen? That sounds quite high - if my calculations are correct, we would lose all our oxygen in around 131,000 years. Where is oxygen being replenished from, if anywhere? – Michael Nov 20 '16 at 21:08
  • @Michael it's likely replenished by life. If memory serves, photosynthetic plankton in the oceans produce something like 300B tonnes of oxygen annually. – BMF Nov 29 '22 at 18:08
  • @BMF ah, ok. Puts a bit of a kink in the oxygen cycle though; I've never seen one showing oxygen escaping into space... – Michael Nov 29 '22 at 18:34
  • @Michael hmm, well... If 1 m^3 of O2 at STP masses 2 kg (ballpark), and we lose one of those every second (~86,000 seconds in a day), that's ~172 tonnes of O2 per day. Compared to nearly 1B tonnes produced daily. More oxygen is probably lost to chemically-reducing substances across Earth than to space. – BMF Nov 29 '22 at 18:56
  • @BMF That's true, although it's technically not lost to chemically-reducing substances, it's just locked up and trapped in them. Oxygen lost to space is probably gone forever. – Michael Nov 29 '22 at 19:03
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The lighter gases in the atmosphere (hydrogen, helium) do escape and are far less abundant than in the universe generally. To escape gravity any object needs to reach a speed of 11 km/s. The heavier molecules left in the atmosphere ($O_2, N_2, H_2O, CO_2$) have very little chance of reaching escape speed by chance, based on the average atmospheric temperature. (see typical speeds of various atoms in Maxwell Botzmann distribution at 298K.)

Other factors are the Earth's magnetic field, which shields the atmosphere from the cosmic wind, and the stabilising effect of life on the surface of the planet, which interacts with the atmosphere. There is also a continuous supply of gases from volcanic activity and radioactivity within rocks inside the Earth. All of these effects have reached a dynamic equilibrium which changes little over thousands of years.

sammy gerbil
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