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A problem I study reduces to whether the polyhedron $P=\{\mathbf{x}\mid A\mathbf{x}=\mathbf{1}, \mathbf{x}\geq0\}$ is integral ($A$ is a matrix with coefficients in $\{0,1\}$). I know that the unimodularity of $A$ is a sufficient condition, which has been useful for me. I want to know whether there is any weaker condition.

I read from a textbook that $P$ is integral if the system $A\mathbf{x}=\mathbf{1}, \mathbf{x}\geq0$ is totally dual integral (TDI), i.e., the minimum in

$\max\{\mathbf{c}^T\mathbf{x}\mid A\mathbf{x}=\mathbf{1}, \mathbf{x}\geq0\}=\min\{\mathbf{y}^T\cdot\mathbf{1}\mid \mathbf{y}^TA\geq \mathbf{c}^T\}$

has an integral optimum solution $\mathbf{y}$ for each integral $\mathbf{c}$ for which the minimum is finite.

This definition is too abstract for me. I wonder whether there is any characterization for this condition that I can use directly.

Surpass2019
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