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Let $j$ be some integer which is neither 0 nor 1. The Galois cohomology space $H^1({\mathbb Q}_p,{\mathbb Q}_p(j))$ is then 1-dimensional, and thus there is a unique non-split 2-dimensional local Galois representations $\rho_j$ with ${\mathbb Q}_p(j)$ as a sub and ${\mathbb Q}_p$ as a quotient.

I think that $\rho_j$ is crystalline if $j>1$, and not crystalline if $j<1$. (One can just write down all of the 2-dimensional reducible admissible modules, and this should follow...I hope.)

Now take $\rho_j$ and restrict it to the absolute Galois group of ${\mathbb Q}_p(\mu_p^\infty)$. This restricted representation then looks like $\begin{pmatrix} 1 & \psi \newline 0 & 1 \end{pmatrix}$ when $\psi$ is some additive character of $G_{{\mathbb Q}_p(\mu_p^\infty)}$.

My question: Should we be able to explicitly describe this character $\psi$? For instance, is $\psi$ an unramified character?

sibilant
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  • Can't this be done for most $j$ using Soule's cocycle, that is, for all $j$ such that $\zeta_p(j)\neq 0$? (Perhaps you don't need the non-vanishing for this, but only when you're looking at some other extension coming from the projective line minus three points. I'm too lazy now to look this up.) – Minhyong Kim Dec 15 '10 at 03:16
  • Although it's not very explicit, you can say that $H^1(G_{Q_p(\mu_{p^\infty})},Qp)$ is a $\Lambda$-module and by the inflation-restriction map you character is in the part on which $\Gamma$ acts by $\chi^j$. If you're wondering what $H^1(G_{Q_p(\mu_{p^\infty})},Qp)$ looks like, the theory of $(\varphi,\Gamma)$-modules may help... – Laurent Berger Dec 15 '10 at 08:31

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