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If $R\mathrel{:=}\mathbb{R}[x_1,\dotsc,x_{n+1}]/(x_1^2+\dotsb+x_{n+1}^2-1)$ and $S^n\mathrel{:=}\operatorname{Spec}(R)$ is the real $n$-spere, a classical result of Borel and Serre says that the only real spheres with an almost complex structure is $S^2$ and $S^6$. An almost complex structure is an endomorphism of the tangent bundle $$J: T_{S^2} \rightarrow T_{S^2}$$ with $J^2=-\operatorname{Id}$. In the case of the real 2-sphere it follows the tangent bundle $T_{S^2}$ is a real algebraic vector bundle of rank 2.

Question 1: I'm looking for an example of a real algebraic (even dimensional) manifold $M$ with an almost complex structure $J:T_M \rightarrow T_M$, where $J$ is not algebraic. The problem of constructing a holomorphic structure on $S^6$ — is this still an open problem?

Note: If you let $k\mathrel{:=}\mathbb{R}$ and $K\mathrel{:=}\mathbb{C}$, it follows there is an isomorphism $$\operatorname{Spec}(K\otimes R)\cong \operatorname{Spec}(B)\mathrel{:=}S^2_K$$ with $$B\mathrel{:=}K[u,v,w]/(uv-(w^2+1)).$$

If $J_K$ is the pull-back of $J$ to $S^2_K$ it follows that $$\phi\mathrel{:=}\frac{1}{2}(I+iJ) \in \operatorname{End}(T_{S^2_K})$$ is an idempotent: $\phi^2=\phi$ and you get a direct sum $$T_{S^2_K} \cong L_1\oplus L_2$$ with $L_i \in \operatorname{Pic}(S^2_K)$. If $J$ is algebraic it follows $L_i$ are algebraic, and I'm interested in this decomposition.

In the case of the real 6-sphere $S^6$ it follows the endomorphism bundle $\operatorname{End}(T_{S^6})$ is a real algebraic vector bundle of rank $36$. We may consider the subvariety $$I(S^6)\mathrel{:=}\{J \in \operatorname{End}(T_{S^6}): J^2=-\operatorname{Id}\}$$ and the group scheme $G\mathrel{:=}\operatorname{GL}(T_{S^6})$. There is a canonical action $$\sigma: G \times I(S^6) \rightarrow I(S^6)$$ and a "parameter space" $I(S^6)/G$ parametrizing algebraic almost complex structures on $S^6$. Is this construction used in the study of the Hopf problem — the problem of constructing a holomorphic structure on $S^6$? If there is a holomorphic structure on $S^6$ — is this neccessarily algebraic? I ask for references.

Note: We may also consider the ring $R\mathrel{:=}C^{\infty}(S^6)$ and the $R$-module $T^{\infty}_{S^6}$ of smooth sections of $T_{S^6}$, and the projective $R$-module $\operatorname{End}_R(T^{\infty}_{S^6})$. We may consider a smooth almost complex structure $J\in \operatorname{End}_R(T^{\infty}_{S^6})\cong \Omega^{1,\infty}_R\otimes_R T^{\infty}_{S^6}$. We get a topological subspace $I^{\infty}(S^6)$ of smooth almost complex structures on $S^6$ equipped with an action of the group of smooth automorphisms of $T^{\infty}_{S^6}$. This is a topological subspace of a smooth vector bundle of rank $36$, and the orbit space parametrize all smooth almost complex structures on $S^6$. Hence if there is a holomorphic structure on $S^6$ it "lives" in this orbit space.

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    The existence of complex structure on $S^6$ is somewhat sensitive topic, but to my best knowledge the community consensus is that it's still very much an open problem. – M.G. Apr 14 '21 at 15:20
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    You can take any almost complex structure which is not integrable and is algebraic, and then patch in local coordinates with a locally defined complex structure, using bump functions, so you get integrability on an open set, but not everywhere. It is easiest to see using complex linear coframings. – Ben McKay Apr 14 '21 at 15:55
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    Take any symplectic manifold with $b_1$ odd, for example Thurston's example https://www.math.stonybrook.edu/~milivojevic/symplecticAUG30stonybrook2018.pdf This cannot be algebraic because $b_1$ would have to be even. Any symplectic manifold admits almost complex structure compatible in a rather nice way with the symplectic form. – Liviu Nicolaescu Apr 14 '21 at 19:44
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    @LiviuNicolaescu: Every compact manifold is diffeomorphic to a real algebraic manifold. The question is not about complex algebraic manifolds, only real ones, so $b_1$ is not relevant. – Ben McKay Apr 15 '21 at 09:49
  • @M.G. - can you specify "sensitive topic"? –  Apr 16 '21 at 10:17
  • @hm2020: it's a somewhat sensitive topic because there have been a few purported proofs from experts in the field in the past 10 years or so in both directions (existence or non-existence), including Atiyah himself, that appear to contain gaps, which can sometimes be the source of disagreements. There are a few questions on MO somewhat reflecting that history, for example https://mathoverflow.net/questions/1973/is-there-a-complex-structure-on-the-6-sphere as well as the questions linked there or related to it. It is a famous open problem after all. – M.G. Apr 16 '21 at 15:29

1 Answers1

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Let $M=SU_3$, the compact semisimple Lie group.

By request of the OP, for those unfamiliar with Maurer-Cartan form, let me define it. Write each point of $SU_3$ as a matrix $g$. Left translation by $g^{-1}$ takes $g$ to $I$, so takes $T_g SU_3$ to $T_I SU_3$. Consider any tangent vector $A\in T_g SU_3$ as a $3\times 3$ complex matrix, since $SU_3$ sits in the vector space of $3\times 3$ complex matrices. We have a linear map $A\in T_g SU_3\mapsto g^{-1}A\in T_I SU_3$, just the derivative of left translation (as the derivative of linear map on a vector space is that same linear map, and then restrict from all $3\times 3$ matrices to the linear subspace $T_g SU_3$). We define the left invariant Maurer Cartan form $\omega$ to be the linear map which takes each tangent space $T_g SU_3$ to $T_I SU_3$ by $\omega_g(A)=g^{-1}A$. So $\omega$ is a $1$-form valued in $\mathfrak{su}_3=T_I SU_3$. (This is all very standard, in every Lie group textbook.) Naturally, one writes this form not as $\omega$ but as $g^{-1}dg$.

As requested: for more information about the Maurer-Cartan form (for any Lie group, real or complex or $p$-adic):

Chevalley, Claude, Theory of Lie Groups. I., Princeton Mathematical Series, vol. 8. Princeton University Press, Princeton, N. J., 1946. ix+217 pp. 152 section V.IV.

Sharpe, R. W., Differential geometry. Cartan's generalization of Klein's Erlangen program. With a foreword by S. S. Chern. Graduate Texts in Mathematics, 166. Springer-Verlag, New York, 1997. xx+421 pp. ISBN: 0-387-94732-9, p. 96.

Write the left invariant Maurer--Cartan form $g^{-1}dg$ as $\omega=(\omega_{\mu\bar\nu})$ for $\mu,\nu=1,2,3$. The coframing $\omega_{1\bar{1}}+i\omega_{2\bar{2}},\omega_{1\bar{2}},\omega_{1\bar{3}},\omega_{2\bar{3}}$ is complex linear for a unique left invariant complex structure. Take a function $f(g)=e^{-|g_{1\bar{2}}|^2/\varepsilon}$, or your favourite nonzero nonalgebraic function. The coframing $\omega_{1\bar{1}}+if\omega_{2\bar{2}},\omega_{1\bar{2}},\omega_{1\bar{3}},\omega_{2\bar{3}}$ continues to have linearly independent real and imaginary parts, so is still complex linear for a unique almost complex structure. But since $f$ is not holomorphic and is not constant, there is a nonzero Nijenhuis tensor. You could also take $f$ to be instead some smooth function with support in some small compact set, and then you get complex structure on some open set turning smoothly almost complex, not complex, on some other open set, so clearly not algebraic or even analytic.

To clarify, as requested: as $SU_3$ is a Lie group, its tangent bundle is trivial as a smooth real vector bundle. Consider the linear map $\Omega \colon TSU_3\to \mathbb{C}^4$ given by $\Omega(v)=(\omega_{1\bar{1}}+i\omega_{2\bar{2}},\omega_{1\bar{2}},\omega_{1\bar{3}},\omega_{2\bar{3}})$ and $\Omega_{\varepsilon} \colon TSU_3\to \mathbb{C}^4$ given by $\Omega(v)=(\omega_{1\bar{1}}+if\omega_{2\bar{2}},\omega_{1\bar{2}},\omega_{1\bar{3}},\omega_{2\bar{3}})$. Let $J_0$ be the standard almost complex structure on $\mathbb{C}^4$. Let $J(v)=\Omega^{-1}(J_0\Omega(v))$. Let $J_{\varepsilon}(v)=\Omega_{\varepsilon}^{-1}(J_0\Omega_{\varepsilon}(v))$. These are my almost complex structures: elements of $\operatorname{End}T_{SU_3}$. You can compute from the Maurer-Cartan equations that $J_0$ is a complex structure, and that $J_{\varepsilon}$ has zero Nijenhuis tensor (so arises from a complex structure) on any open set where $f=0$, but not near any point where $df\ne 0$.

The complex structure on $SU_3$ is homogeneous under left action of $SU_3$. It is not Kähler, as $b_2(SU_3)=0$, so all closed 2-forms are exact, and hence no symplectic form on $SU_3$. In particular, $SU_3$ does not have a complex structure under which it could become a Kähler manifold, and a fortiori is not a complex algebraic variety. There are infinitely many nonbiholomorphic complex structures on $SU_3$ invariant under left $SU_3$ action.

Note that $SU_3$, in any complex structure, is not a complex Lie group, i.e. its multiplication is not holomorphic. Proof: Indeed $SU_3$ is compact. Take a compact complex Lie group $G$. Take a complex linear finite dimensional representation of $G$. The representation is a map to complex matrices, which form an affine space. Complex affine space has no compact complex subvarieties except points. So $G$ has discrete image. So $G$ has discrete adjoint representation. Hence the identity component of $G$ is an abelian group, compact, so a complex torus. So compact complex Lie groups are precisely finite group extensions of complex tori. In particular, since $SU_3$ is connected and nonabelian and compact, it is not a complex Lie group for any complex structure. If its multiplication were holomorphic for some complex structure, then the holomorphic implicit function theorem would ensure that its inverse operation was also holomorphic, so it would be a complex Lie group.

For more information about this and other $SU_3$-invariant complex structures on $SU_3$ (and all other compact and simply connected homogeneous complex manifolds) see

Hsien-Chun Wang, Closed manifolds with homogeneous complex structure, American Journal of Mathematics, vol. 76, no. 1 (January 1954), pp. 1-32.

Phillip Griffiths, On certain homogeneous complex manifolds, Proceedings of the National Academy of Sciences of the United States of America, vol. 48, no. 5 (May 15, 1962) pp. 780-783.

Ben McKay
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  • I ask you to write this answer in terms of the tangent bundle $T_M$, its vector bundle of endomorphisms $End(T_M)$, possibly using the Serre-Swan theorem and the module of smooth sections of $T_M$. –  Apr 15 '21 at 13:10
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    From your comments, my impression is that my description of an example is not to your taste. I have never seen an almost complex structure described using the Serre-Swan theorem or in terms of vectors fields as forming a module, so I will need some idea of how you prefer to write almost complex structures if I am to provide a clearer description. Perhaps you can give an example of almost complex structures from your preferred perspective. – Ben McKay Apr 15 '21 at 15:40
  • as a differential geometer you are used to using local coordinates, with background in algebra/geometry I use sheaves of functions and sheaves of sections of vector bundles. Hence an almost complex structure in my language is an endomorphism $J$ of the tangent bundle (which is a projective $R$-module of rank $2$) with square $=-Id$. If in a local trivialization $J$ is defined using "rational functions", $J$ is algebraic. If $J$ is locally defined using smooth functions it is smooth. –  Apr 15 '21 at 17:27
  • The real Lie group $SU(3)$ is 8-dimensional and its real tangent bundle is trivial of rank 8: $T_{SU(3)}\cong SU(3) \times \mathbb{R}^8$. It seems to me that $\Omega_{\epsilon}$ can not be inverted as you claim - it is a map from a real Lie group to a 6-dimensional real vector space. Is there a mistake? –  Apr 16 '21 at 09:47
  • Right: it is 8-dimensional. Fixed – Ben McKay Apr 16 '21 at 09:50
  • let $H:=SU(3)$. It seems to me the map $\Omega$ should be a map $\Omega: T_H \rightarrow H \times \mathbb{C}^4$ with $\Omega(x)=(x,\phi(x))$ for some function $\phi$. Can you specify the map $\phi$? It seems you have chosen a trivialization $T_H \cong H\times \mathbb{C}^4$ and consider a map $\Omega \in End( H \times \mathbb{C}^4)$ which is invertible. –  Apr 16 '21 at 10:22
  • A 1-form is a linear map of tangent vectors to numbers. The map $\Omega$ is a vector-valued 1-form, so a map $\Omega \colon T_H \to \mathbb{C}^4$, which you can call $\phi$. – Ben McKay Apr 16 '21 at 11:53
  • Let $H:=SU(3)$. $H$ is a real algebraic manifold and it seems to me you have constructed a holmorphic structure $H_{\mathbb{C}}$ on $H$ above. Are you claiming that $H_{\mathbb{C}}$ is a non-algebraic complex manifold? –  Apr 16 '21 at 14:59
  • The complex manifold $H_{\mathbb{C}}$ is a real Lie group - are the multiplication and inversion map holomorphic maps, ie is $H_{\mathbb{C}}$ a complex Lie group? –  Apr 17 '21 at 11:18
  • it seems to me the 1-forms you introduce take values in the complex numbers $\omega_{ij} \in \mathbb{C}$. Since $SU(3)$ is an affine variety we may write $SU(3):=Spec(R)$ where $R$ is the coordinate ring of $SU(3)$. A 1-form $\omega_{ij}$ gives canonically an element $w_{ij}\in Hom_R(Der_k(R),R)$ where $Der_k(R)$ is the module of derivations of $R$, hence $\omega_{ij}$ is never a complex number. I ask for a more detailed explanation of your notation.... –  Apr 20 '21 at 11:52
  • Since $T_{SU(3)}$ is trivial of rank 8 there should be an isomorphism of $R$-modules $Der_k(R) \cong R^8$. Hence $\omega_{ij}\in Hom_R(R^8,R)\cong R^8$. And $R^8$ is never isomorphic to $\mathbb{C}^4$. –  Apr 20 '21 at 11:55
  • A complex-valued 1-form yields a complex valued function when you plug in a vector field: $\omega_{ij}\in\operatorname{Hom}R(\operatorname{Der}_k(R),R\otimes{\mathbb{R}}\mathbb{C})$. – Ben McKay Apr 20 '21 at 12:09
  • Yes - here you write down some 1-forms - which forms are the forms $\omega_{ij}$ - can you give an explicit formula? They should be explicit elements in $\Omega^1_{T_{SU(3)}}$ and then you must choose a presentation of $\Omega^1_{T_{SU(3)}}$. –  Apr 20 '21 at 12:36
  • I cannot find a description in the literature of the Maurer-Cartan form in the context of group schemes, for example, so I am using a concept from differential geometry here: these $\omega_{\mu\bar\nu}$ are the matrix entries of the left invariant Maurer-Cartan form, for which I do not know of a description in the sort of algebraic language you are using. – Ben McKay Apr 20 '21 at 12:37
  • it seems the Maurer-Cartan form is something that exists for a general $2n$-dimensional real Lie group - does the construction above generalize to other such Lie groups? Do you have references? –  Apr 21 '21 at 07:18
  • Has the Maurer-Cartan formalism been treated in the "language of group schemes" - do you know a reference? The book referenced to above is written in "differential geometric language". –  May 20 '21 at 09:14
  • As I remarked above, I don't know of the Maurer-Cartan formalism being treated in the language of group schemes. – Ben McKay May 20 '21 at 09:46