how to change login button to logout when the user is logged in

Question

I have added a login link in Magento top links by using deafult.xml and set the URL as default Magento sign-in URL

default.xml

<block class="Learning\Module\Block\Link1" name="custom-header-linkyy">

                <arguments>
                <argument name="label" xsi:type="string" translate="true">Login</argument>
                <argument name="path" xsi:type="string" translate="true">customer/account/login/</argument>
                </arguments>

          </block> 

     </referenceBlock>

link1.php

<?php
namespace Learning\Module\Block;

class Link1 extends \Magento\Framework\View\Element\Html\Link
{
/**
* Render block HTML.
*
* @return string
*/
protected function _toHtml()
    {
     if (false != $this->getTemplate()) 
     {
     return parent::_toHtml();
     }
     return '<li ><a ' . $this->getLinkAttributes() . ' >' . $this->escapeHtml($this->getLabel()) . '</a></li>';
    }
}

now what I want is when a customer clicks and logged in successfully that button should be changed to logout is there any solution for this thanks in advance

yes am using custom theme but i tried this thing with my custom module but you can suggest if you know a solution by using custom theme that would be even better — Pramod, Jan 07 '20 at 10:11

score 1 · Answer 1 · answered Jan 07 '20 at 10:13

1

In Your Button You Can Check Condition :-

$this->isLoggedIn() ? __('Log Out') : __('Log In')

answered Jan 07 '20 at 10:13

Ronak Rathod

6,322
17
42

can you explain it how?? coz am not using button but rather am using link in default.xml – Pramod Jan 07 '20 at 10:18
how to create login button ?? – Ronak Rathod Jan 07 '20 at 10:19
no how to add this condition and where ?? – Pramod Jan 07 '20 at 10:22

paj · Answer 2 · 2020-01-07T15:37:38.667

Please check this answer which will show you the best way to check for if session is logged in.

Creating a helper to use in your templates:

<?php
namespace MyVendor\MyModule\Helper;

use Magento\Framework\App\Helper\AbstractHelper;

/**
 * Created by Carl Owens (carl@partfire.co.uk)
 * Company: PartFire Ltd (www.partfire.co.uk)
 **/
class Data extends AbstractHelper
{
    /**
     * @var \Magento\Framework\App\Http\Context
     */
    private $httpContext;

    public function __construct(
        \Magento\Framework\App\Helper\Context $context,
        \Magento\Framework\App\Http\Context $httpContext
    ) {
        parent::__construct($context);
        $this->httpContext = $httpContext;
    }

    public function isLoggedIn()
    {
        $isLoggedIn = $this->httpContext->getValue(\Magento\Customer\Model\Context::CONTEXT_AUTH);
        return $isLoggedIn;
    }
}

Then I use the helper in your templates like so:

<?php
$helper = $this->helper('MyVendor\MyModule\Helper\Data');

if ($helper->isLoggedIn()) {
    //show something
}

Taken from : https://magento.stackexchange.com/a/141599/7863

score 0 · Answer 3 · answered Jan 07 '20 at 11:21

You can add Login, Logout button Using Object Manager

$objectManager = \Magento\Framework\App\ObjectManager::getInstance();
$customerSession = $objectManager->get('Magento\Customer\Model\Session');
if($customerSession->isLoggedIn()) {
   // customer login action
}

In Controller

$this->_objectManager->get('Magento\Customer\Model\Session');
if($customerSession->isLoggedIn()) {
   // customer login action
}

Using Helper

<?php $_loggedin = $this->helper('Magento\Checkout\Helper\Cart')->getCart()->getCustomerSession()->isLoggedIn(); ?>

<?php if( $_loggedin ) : ?>

     <div><!-- add your code --></div>

<?php endif; ?>

score 0 · Answer 4 · answered Jan 07 '20 at 11:24

You Can try Below code

Vendor/Module/view/frontend/layout/default.xml

<?xml version="1.0"?>
<page xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="urn:magento:framework:View/Layout/etc/page_configuration.xsd">
    <body>
        <referenceBlock name="header.links">
            <block class="Vendor\Module\Block\Index\Link" name="custom_link" before="authorization-link" template="Vendor_Module::index/link.phtml"/>
        </referenceBlock>
    </body>
</page>

Vendor/Module/Block/Index/Link.php

<?php
namespace Vendor\Module\Block\Index;

class Link extends \Magento\Framework\View\Element\Template
{


    public function __construct(
        \Magento\Framework\View\Element\Template\Context $context,
        \Magento\Customer\Model\SessionFactory $customerSession,
        array $data = []
    ) {
        $this->storeManager = $context->getStoreManager();
        $this->customerSession = $customerSession;
        parent::__construct($context, $data);
    }

    public function isCustomerLoggedIn()
    {
        if ($this->customerSession->create()->isLoggedIn()) {
            return true;
        }
        return false;
    }
}

Vendor/Module/view/frontend/templates/index/link.phtml

<?php

if ($block->isCustomerLoggedIn()) {
    ?>
    <li>
        <a href="<?php echo $block->getBaseUrl() . 'customer/account/login';?>" id="login_form">
            <?php echo __("Log in") ?>
        </a>
    </li>
<?php 
}else{ ?>
    <li>
        <a href="<?php echo $block->getBaseUrl() . 'customer/account/logout';?>" id="logout_form">
            <?php echo __("Log Out") ?>
        </a>
    </li>
<?php }
?>

score 0 · Accepted Answer · answered Jan 08 '20 at 15:33

Please take a look at least how it is implemented in magento 2 currently.

Just go to: vendor/magento/module-customer/view/frontend/templates/account/link/authorization.phtml

and here we got

if($block->isLoggedIn())

Now lets go to the responsible class/block.

vendor/magento/module-customer/Block/Account/AuthorizationLink.php

public function isLoggedIn()

Add this block to your constructor and run isLoggedIn function where you need it or inject the httpContext and apply the logic.

how to change login button to logout when the user is logged in

5 Answers5