The constant G in Newton's law $F = G m_1m_2/r^2$ is, as far as I know, absent from Newton's work - who introduced this constant?
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2It is implicitly present in Newton's work. So one did not have to "introduce" it. Once you choose the units, you get a constant. At the time of Newton, they avoided writing constants depending on the units because the units were not firmly established. They preferred to phrase the laws in terms of proportionality. – Alexandre Eremenko Jan 25 '16 at 22:40
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That's what I mean by absent, and my question is who introduced it, in your terms, explicitly, – Jan 26 '16 at 06:41
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1I don't know but I suppose that physical units were standartized only at the time of French revolution. – Alexandre Eremenko Jan 26 '16 at 21:32
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In theoretical physics research, publication of papers, and graduate (usually) level text books, a number of physical constants are set to 1, the integer 1 -- that is, no units. Obviously this changes the units of most if not all of the other values of a given equation but it simplifies the mathematical work. In quantum field theory work, it is common to set $\hbar=1$, and $c=1$. In Cosmology is is common to set $c=1$ and $G=1$. – K7PEH Jan 28 '16 at 19:25
2 Answers
As a constant using ordinary units (e.g., metric), the gravitational constant G doesn't occur until late in the 19th century. Scientists in Newton's time and into the 18th century were quite happy to work in terms of proportionalities and ratios; the constant of proportionality never needed to be written down. For example, one does not see a gravitational constant, in any form, in Cavendish's description of his experiments to "determine the density of the Earth" (1798). This practice of not using a gravitational constant with regard to earthly matters continued throughout much of the 19th century, e.g., Pratt (1855).
One does see something much akin to the Newtonian gravitational constant in the works of Laplace (1799) and Gauss (1809). Using modern nomenclature, Newton's law of gravitation using the gravitational constant of Laplace and Gauss is $$F = k^2 \frac{m_1 m_2}{r^2}$$
The key differences between that and $F=G \frac{m_1 m_2}{r^2}$ are that the Laplace's and Gauss's $k$ is the square root of the Newtonian constant, and that the system of units is more apropos to modeling the solar system. Gauss explicitly specified his system of units: One mean solar day as the unit of time, one solar mass as the unit of mass, and one astronomical unit (the mean distance between the Earth and the Sun) as the unit of length. The Gaussian gravitational constant has a numerical value of 0.01720209895, as reported by Gauss. This value persisted as a defined constant until very recently (2012, and perhaps later).
Aside: Note that making $k$ a defined constant effectively made the astronomical unit a derived quantity, divorcing it from the size of the Earth's orbit. Keeping $k$ at the value established by Gauss was standard practice throughout the 19th and 20th centuries.
The push to measure $G$ using earthly units didn't occur until after physicists saw the value of the metric system and its predecessors, was largely driven by electromagnetism. A flurry of publications occurred late in the 19th century regarding the Newtonian gravitational constant, apparently starting with Cornu and Baille (1873). (The reason I wrote "apparently" is because I can't access that paper, and because Poynting describes that paper as "brief".) Judging a book by its cover (or a scientific paper by its title), the title "A new determination of the constant of attraction and of the mean density of the Earth" certainly does appear that Cornu and Baille made the connection between assessing the mean density of the Earth and the gravitational constant. Boys (1889) makes the connection very explicit; Boys announced he was going to use a Cavendish experiment to measure the gravitational constant as the primary goal. That this measurement also would yield an estimate of the density of the Earth was secondary.
C.V.Boys (1889), "On the Cavendish experiment", Proc. R. Soc. London, 46, 253-268
C.V. Boys (1894), "The Newtonian constant of gravitation," Notices R. Inst. 14 353-377.
A. Cornu et B. Baille (1873), "Détermination nouvelle de la constante de l'attraction et de la densité moyenne de la Terre," Comptes Rendus lxxvi, 954-8.
Gauss (1809), "Theoria motus corporum coelestium in sectionibus conicis solem ambientium"
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According to Wikipedia: "one of the first references to $G$ is in 1873, 75 years after Cavendish's work."
Newton assumed an inverse square law, as had already been proposed. Inverse square laws are usually due to spherical propagation: something is emitted in all directions from a point, so that at later times it is distributed on the surface of a sphere. This implies velocity, which Newton ignored (or assumed was too fast to mention). He could have conjectured that gravity was spherically propagated, and used $4\pi\cdot r \cdot r,$ instead of just $r\cdot r.$
G is not merely a constant of proportionality. It has units which deserve further attention. It is roughly ($c\cdot c \cdot R / M)/(4\pi),$ where $c=3\mathrm{E}8 ~\textrm{m/s}$ = speed of light (or gravity); $R=4.6\mathrm{E}26~\textrm{meters}$ = radius of visible universe; $M=3\mathrm{E}52~\textrm{kg};$ and $4\pi$ is the neglected spherical factor.
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Yes, but less that 1E-11 woo, which makes it worth consideration, unless you explain... – amI Feb 03 '16 at 18:00
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Unless you can find a citation for that woo in peer reviewed journals, it's just woo. There are lots of citations that claim that G truly is a constant, meaning that it doesn't vary in time. We happen to live at a time where your woo is approximately true, to within an order of magnitude or so. It's numerological woo. – David Hammen Feb 03 '16 at 18:08
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Those citations only claim that G has been constant within a factor of 2. To say that 'now' is so special of a coincidence is harder to believe than that there is new physics to find. – amI Feb 03 '16 at 18:27
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1Nonsense. Let's use different sets of units. In natural units, the speed of light is 1, the radius of the observable universe is $2.7\times10^{61}$ planck lengths, and the mass of the observable universe is $1.5\times10^{62}$ planck masses. Your expression yields a value of 0.014 for G. It should be 1 in this system. Using the astronomical unit as the unit of length, the day as the unit of time, and the mass of the Sun as the unit mass, your expression yields a value of $1.4\times10^{12}$. The correct value of G in this system is $2.959\times10^{-4}$. – David Hammen Feb 04 '16 at 16:23
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My value of M converts to 1.38E60 mp, not 1.5E62 mp. That is why your 0.014 is 100 times too small. Where did you get your value? I think your 2nd example has math errs (I will try to work it through later). Thank you @DavidHammen – amI Feb 09 '16 at 21:31
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I see that your 2.95e-4 is correct, but your 1.4e12 is way off. I hope you can see that the balance of an equation is never affected by change of units. The formula I gave (G=R k c c / 4 pi M; where k is near unity) is not a theory, but it is worth pursuing. – amI Feb 10 '16 at 17:27
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Thanks to whoever edited the math html. I will add that F=Gmm'/rr expands to F=(kR/Mcc)(mcc)(m'cc/4pi*rr), so gravity depends on energy, not mass. – amI Mar 08 '16 at 00:27
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What is the difference of energy and mass in that context as both are said to be the same? What about the constant reconciling inertial with gravitational mass: "...so gravity depends on gravitational, not inertial mass..."? (I think it is worth considering what "g" (not "G") means; it means that "earth's" movement implied by Newton's law of gravitation is neglected when using the same mass unit in F=ma. I wonder if you exclude such argument as not relating to this answer and nonsense. Cheers!) – Peter Bernhard Nov 27 '22 at 14:17