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After being a fan of diverse WW2-games, I was wondering why and how the gun caliber sizes were designed, from the view of history. Is there an explanation why for example the German army choose to step up from 50 mm via 75 mm to 88 mm, and not to 90 mm in caliber? Why did they choose that "uneven" (imho) gun diameter? Furthermore, the guns increase from 105 mm (reasonable) to 128 mm. Again: Why not an even value, such as 130 mm? Similar approaches can be done for the US tanks (76 mm for example, even though that is close to 3 inches).

Thus, is there a historical reason for such odd caliber sizes, or rather a physical reason?

Schwern
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arc_lupus
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  • I know that the German Army adopted the 88mm calibre from the Kaiserliche Marine (Navy) when it introduced the 88mm anti-tank gun in 1917. I assume the Kaiserliche Marine adopted the 88mm calibre based on the weight of the shell (approx 25 pounds). The 75mm developed by Krupps in the inter-war period was in partnership with the Swedish company Bofors - which might be why they went with a different calibre. – sempaiscuba Jul 03 '17 at 18:59
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    And the 128:"The choice for 128 mm calibre anti-tank gun was made because of the availability of tooling due to the use of this calibre for naval weapons." This is a 5" naval gun,adapted. . Each caliber would have its own story. – justCal Jul 03 '17 at 19:03
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    There is certainly a correlation between projectile weights and some odd calibres used by the British military. The "17 pounder" of WW2 had a 3 inch (approx 76mm) calibre. The "25-pounder" had a calibre of 3.45 inches (approx 88mm). – sempaiscuba Jul 03 '17 at 19:05
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    What is "f.eks."? – David Richerby Jul 03 '17 at 21:32
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    @DavidRicherby Abbreviation of "for eksempel", Danish for "for example". – Schwern Jul 03 '17 at 23:10
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    You could apply this same question to most every weapon throughout history. Why have there been so many types and sizes of swords or spears or polearms or bows, etc.? Between different purposes (do you care more about range or weight or speed or damage or defeating armor or matching a particular style of combat....) and different constraints (does is need to be as cheap as possible, as easy to use as possible, does it need to be especially durable or reliable...), you quickly realize there are a lot of ways to make a weapon, all with advantages and disadvantages, but no universal best way. – HopelessN00b Jul 04 '17 at 08:12
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    @HopelessN00b While there have been as many different types of firearms as there is combat, the question is about firearm calibers. Firearms have a pressure to use common calibers to share ammunition and barrels. This greatly simplifies logistics, production, and supply. Melee weapons require no such commonality. – Schwern Jul 04 '17 at 19:43
  • @Schwern Melee weapons (and bows, for an example of ranged weapons that aren't firearms) tend to standardize as well, despite not having to share ammunition (as you mention). This tells us that the pressure to share ammunition isn't the whole story, as does the fact that there are dozens of different gun calibers in the first place. I'm reminded of the issue of triangular bayonets in WWI - they were cheaper and as effective as knife-style bayonets, but their wounds don't heal properly, so they're banned. Another example of the unexpected considerations that pop up in designing weapons. – HopelessN00b Jul 04 '17 at 20:18
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    @HopelessN00b Weapons tend to cluster around certain designs (a style of sword, or type of locking mechanism), but only firearms around certain measurements because of the ammunition constraints. And while there are many, many, many calibers, militaries cluster around just a few. Triangular bayonets being banned is, I believe, a myth; I cannot find any evidence for a ban. The reality is it was heavy, the tip tended to break off, they're not useful as a knife so you had to carry a knife as well, and WWI made bayonets obsolete. – Schwern Jul 04 '17 at 20:29
  • I've made a chat room to continue these side discussions. https://chat.stackexchange.com/rooms/61565/weapons-and-bayonets-and-calibers-oh-my – Schwern Jul 04 '17 at 20:59
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    @arc_lupus the english version of "f.eks" is probably "e.g." (exempli gratia) which sounds a bit like the egg in example which is how I try to remember it. Not to be confused with "i.e." (id est)(that is)(in other words) which could be remembered as 'In Essence'. Basically when submitting to an english language site, you may want to use latin that no one really understands that danish. Though I think f.eks sounding like made up rude irish world should win the Danes bonus Internet points. – TafT Jul 06 '17 at 07:48

4 Answers4

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Why not an even value, such as 130 mm?

Neat Numbers Don't Kill The Enemy

The general answer to that is because the design goal is to make the best gun possible, not have the numbers come out neatly. The engineers designing and building the gun don't care if it's in neat numbers. They might start with one neat number, but derived dimensions are subservient to engineering considerations and calculations.

Use What's Available

This is probably the most important reason why large caliber guns are the caliber they are: there's already tooling to produce the parts in that caliber, particularly the expensive rifled barrels. For example, the German 12.8 cm Pak 44 used tooling in common with the 12.7 cm SK C/34 naval gun used on German destroyers.

Then there's ammunition commonality. Just having the same caliber doesn't mean you can share ammunition, there's many other considerations, but it helps. If all your guns can share ammunition that simplifies production, logistics, and supply.

For small arms, small differences in ballistic performance are not terribly important; tactics dominate small arms engagements. Instead the problem is supplying large amounts to large numbers of troops who will use it for various tasks, and they have to carry it. Logistics becomes paramount. For this reason, most militaries, in contrast to civilians, have standardized around just a few small arms rounds. One pistol round (9x19mm or 9×18mm), one intermediate round (5.56x45mm NATO or 5.45×39mm Soviet), and one full power rifle round (7.62×51mm NATO or 7.62×54mmR).

Large caliber firearms tend to be specialized, vehicle mounted, and fire less ammunition. They fill the roles of anti-tank, anti-aircraft, and artillery. These fields were in an intense arms race, particularly during WWII until roughly the 1980s when electronics took over, so you could get an advantage out of fielding a new round that offset the logistical problems. As a result militaries can afford a lot of diversity in large calibers, but they still tend to cluster around certain historical calibers that they (or who they're buying from) are already producing.

Adapted From Quirky Old Naval Guns

Large caliber artillery and tank cannons are often adapted from naval guns and anti-aircraft guns (which also often come from naval guns). Both naval and anti-aircraft guns require long range, high muzzle velocity (naval guns for armor penetration, AA for altitude), and large calibers to pack sufficient explosive or kinetic energy to do damage. Anti-aircraft guns are often preferred because they're designed to be lighter, and more mobile than naval guns.

Naval guns have been around for a long time, so tanks and artillery inherit the naming and size quirks of old naval guns.

For example, the famous German 88 began life as AA gun which itself began as a naval gun. The US 90mm also started as an AA gun (the 90mm M1 and M2) and was adapted into the M3 tank cannon for the M36 Tank Destroyer and M26 Pershing.

It's Just A Name

There are various ways to name a round. Wikipedia puts it this way.

Due to variations in naming conventions, and the whims of the cartridge manufacturers, bullet diameters can vary widely from the diameter implied by the name.

There are so many numbers to choose from! Have a look at 5.56x45mm NATO.

enter image description here

Look at all those numbers to choose from! You can use the chamber diameter, the case diameter, the bore diameter, the bullet diameter... If rifling is involved, you can use the diameter as measured at the lands (the smaller diameter formed by the ridges) or the grooves (the larger diameter formed by the troughs between the ridges). For example 9x19mm Parabellum and 9x18mm Makarov do not have the same bullet diameter. 9x18mm Makarov measures caliber between the lands, so the bullet is 9.27mm in diameter. 9x19mm measures between the grooves, so the bullet is 9mm in diameter.

And you can just make shit up.

For example, no part of 5.56x45mm NATO is 5.56mm. The bullet is 5.70mm at its thickest, same as its parent the .223 Remington. 5.70mm is .224" so even the .223 Remington isn't .223". The closest thing to 5.56mm about 5.56mm is the pilot diameter, which is the size of the hole which guides the bullet into the rifling, and even that isn't quite 5.56mm.

So the number in the name is just a name, divorced from the actual engineering specifications.

Inches, Pounds, Millimeters

Sometimes odd metric designations are because they began life in another measurement. 12.7cm and 12.8cm are actually 5 inch guns. 76mm is 3 inches, etc...

Then there's the British "pound" system like the "3-pounder". This is how much round, solid shot would weigh and goes waaaaay back in British naval history. A 3-pound gun is 47mm which explains why we had 47mm weapons.

Volume Is The Square Of The Caliber

When you increase the caliber, and keep the length the same, the volume of the case increases by the square of the caliber. That means bigger shells (now you can store less shells), more weight (good luck humping that round, loader), and more material (higher cost per round).

Using your example of going from 128mm to 130mm, the brass case of a Mark 10 shell for a US 5"/38 gun is 127x679mm and weighed 5.58kg. A shell case is an open topped cylinder with a surface area of 2πrh + πr^2. 127mm is 283,433 m^2. 130mm is 290,434 m^2. That's an increase of 2.5% or 140 grams of brass (probably more since the base is thicker than the walls). Volume is πr^2h and goes up by ~5% which means more powder.

The numbers get worse for the barrel. The 5"/38 is 5683mm long and weighs 1,810 kg. If we increase its surface area by 2.5% that's an extra 45 kg of high quality steel. That extra weight means a stronger mounting which means more weight which needs stronger drives to rotate it, etc.

Note that these are very back of the envelope calculations. Point is, even a small change in diameter can have a large effect.

Please keep in mind this is not a practical example of scaling up a round, I deliberately left the length the same and ignored a host of other issues because they're outside the scope of the question. It's only rough calculations intended to illustrate the knock-on effects of changing the caliber even by a few millimeters. And yes, as the caliber (radius) changes, but the length remains the same, the volume changes by the square of the caliber; that is not a mistake. If you want to edit it with more accurate calculations that don't clutter the answer, please do. If you want to talk about this more, please do it in chat.

Specific Calibers

Many caliber names trace back to the 1890s up to WWI when changes in gun and ammunition was happening fast, and nobody fussed too much about naming standards because they needed guns for the front NOW.

Others are simply their metric versions of older imperial standards.

155mm

Roughly 6.1 inches. This traces back to the French WWI Canon de 155 C modèle 1915 Schneider which took an earlier 152mm (6 inches) and upped it to 155mm (6.1 inches). Why switch to 6.1", I don't know.

152mm

6 inch naval gun.

12.7/12.8cm

The ubiquitous 5 inch naval gun.

105mm

Roughly 4.1 inches. Traces back, in German service, to the 10.5 cm Feldhaubitze 98/09 from 1902.

102mm

4 inches.

90mm

3.5 inches.

88mm

Possibly from the British 25-pounder (not the Ordnance QF 25-pounder from the 1930s, but the caliber measurement). The 88 in German service is originally from the "quick firing" 8.8 cm SK L/30 naval gun dating back to 1892.

76mm

3 inches or 17-pounder.

75mm

From French Canon de 75 modèle 1897. Adopted by the US to have commonality with French equipment in WWI.

57mm

6-pounder.

47mm

3-pounder.

I can trace this back to the 18th century Grasshopper. In modern times it began with the QF 3 pounder Nordenfelt and the Canon Hotchkiss à tir rapide de 47mm, quick-firing naval guns both designed in 1885.

45mm

AFAIK only used by the Soviets. They scaled up a German 37mm anti-tank gun in 1932 to make the 45 mm anti-tank gun M1932 19-K. According to Wikipedia 45mm was chosen because...

The reason for selecting 45 mm caliber was the large reserves of the French 47 mm shells which can be converted to 45 mm by milling out the driving bands.

Why they chose 45mm instead of 47mm I'm not sure.

40mm

2-pounder.

37mm

1.5 inch, and 1-pounder.

Earliest modern use I can find is the QF 1-pounder pom-pom 37mm autocannon from the late 1880s.

25mm

1 inch.

Earliest reference I can find is the French 25mm Hotchkiss anti-tank gun proposed in 1926 to replace the 37mm infantry gun with better armor piercing capability. The Japanese used a local variant as the Type 96 25 mm AT/AA Gun.

Schwern
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    Great answer. And let's not forget that increasing projectile diameter decreases velocity, all else being equal. – Tony Ennis Jul 03 '17 at 23:15
  • And at the smaller end, 12.7mm is .50-caliber (half an inch), while 7.62mm is .30-caliber (0.3 inch). – Mark Jul 04 '17 at 00:27
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    Your math doesn't make sense. For one thing, squaring volume doesn't make sense - it's a dimensional error. Squaring a volume doesn't give something in units of volume. I think you wanted to say that increasing the caliber by a factor of x increases the volume by a factor of about x^3 (making the approximation that all dimensions scale equally). – user2357112 Jul 04 '17 at 00:35
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    @user2357112 The formula for the volume of a cylinder is V = π r^2 h. Changing the caliber changes r, but h remains constant. Since it's r^2 if you double the radius (caliber) you quadruple the volume. If r = 2, V = 4πh. If r = 4, V = 16πh. The dimensions work out to m^3 from r^2 h. I made the same mistake you did in my first draft confusing it with the volume of a sphere. – Schwern Jul 04 '17 at 00:59
  • @Schwern: Okay, but you're still saying to square the volume itself instead of squaring the factor by which you scaled the caliber. (Having much less familiarity with projectile weapons than I have with math, I don't know how the length tends to scale with the caliber, so I can't say whether it makes sense to hold the length constant. Similarly, at one point you take brass volume to be proportional to surface area, and I can't say whether it makes sense to hold the case thickness constant as you seem to be doing.) – user2357112 Jul 04 '17 at 01:06
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    @user2357112 All other things being equal, volume increases as the square of the caliber. And the OP is only asking about caliber. The length of the cartridge is not related to the caliber. For example, a 9mm pistol round is just 19mm long, while the 5.56mm NATO rifle round is 45mm. Yes, in reality you'd probably have to scale the thickness of the brass, too. Like I said, these are back of the envelope calculations meant to point out the knock on effects of even a small increase in caliber. – Schwern Jul 04 '17 at 01:15
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    As already mentioned, I think it's pretty counterintuitive to leave the length of the bullet constant when scaling up the caliber, since it would negatively impact the bullet's aerodynamics. It's much more reasonable to consider the scaling as roughly cubic, since modern bullets of a similar design often scale up along all 3 spatial axes, see this Wikipedia image comparison, with the exception of the .22 LR, which has a different design altogether – March Ho Jul 04 '17 at 03:25
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    In addition, using the correct conversion ratio (cube instead of square) only serves to strengthen your point, not weaken it. – March Ho Jul 04 '17 at 03:31
  • Many dimensions might also be artefacts of earlier measurement systems - what used to be a 3 inch barrel might nowadays be considered a 3.1" or 2.9" or whatever. The measurements weren't globally standardised, that only came with the late metric system. When people switch to a new measurement system, it doesn't change the reality (the barrel is still the same size), but it does change the name (what used to be "even" is no longer "even"). – Luaan Jul 04 '17 at 09:17
  • I think British 25 pounder is from 1930s so 88mm does not come from that – mmmmmm Jul 04 '17 at 10:19
  • A nice answer, but where is the 45mm antitank and 25mm and 37mm airplane guns? And yes, twice diameter means 8 times volume, not 4! – Gangnus Jul 04 '17 at 15:02
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    A nice example of the arbitrariness of nomenclature is to observe that the .38 Special and .357 Magnum both use identical barrels, despite the 6% difference in numerical value. – supercat Jul 04 '17 at 15:57
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    I've created a chat room for the side discussions, especially for going on and on about the volume thing, sheesh! https://chat.stackexchange.com/rooms/61565/weapons-and-bayonets-and-calibers-oh-my – Schwern Jul 04 '17 at 21:00
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    @Gangnus I can't do every caliber, but I've added those in. Twice the diameter means 8 times the volume for a sphere. Cases are a cylinder, V = π r^2 h. If you double the diameter of the base, but leave the length/height of the cylinder the same, it increases the volume by 4. Please take more discussion about that to the chat. – Schwern Jul 04 '17 at 21:43
  • "Why they chose 45mm instead of 47mm I'm not sure" It is simple. Having the same shoot, but 5% smaller barrel and thus 15% lighter gun. – Gangnus Jul 04 '17 at 22:20
  • Yay imperial units! So they are round numbers after all. – RedSonja Jul 05 '17 at 12:29
  • @Schwern Teach me about shotgun shells /gauge too please. Should I make it a new question? – USER_8675309 Jul 05 '17 at 14:21
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    Shotgun gauges were derived from "this many lead balls of bore diameter to the pound"... Would make a good question, though. – Adrien Jul 05 '17 at 19:34
  • @USER_8675309 If you can make it history related, and beyond what's already in the Wikipedia article on shotgun gauges, ask away! AFAIK the history of shotgun gauges is a lot more straightforward than gun calibers, but I don't know much about shotguns. – Schwern Jul 05 '17 at 21:29
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"Interior ballistics," the art of getting projectiles to come out of gun barrels spinning correctly, at the desired speed, and without unexplained wobbles, is complex. As recently as the 1980s, FN Herstal, who are a pretty competent arms company, were unable to make their planned 15mm calibre FN-BRG machine gun work in a satisfactory way, and had to switch to 15.5mm calibre. Naturally, this sort of problem was more common in the nineteenth and early twentieth centuries. And round numbers don't actually provide any engineering advantage.

Once a calibre has gone into use, there are many advantages from sticking with it. Having as few sizes of ammunition as possible is very helpful for wartime logistics. Guns can be improved by upgrading the ammunition. Better ammunition can be used in new guns. And even if you need a gun with quite different characteristics, there's often production plant that can be re-used more easily if it's for the same calibre.

So there was a substantial random element in the initial selection of calibres, and once a calibre is widely used, there are few advantages and major disadvantages in changing to another one for the same kind of work.

John Dallman
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    Captain obvious: round numbers are tied to their measurement system. Change the units, and you change what actual physical dimension corresponds to a round number. It would be rather surprising if changing a country's measurement system changed the performance of its weaponry :D (though it certainly can make communication more difficult). – Luaan Jul 04 '17 at 09:19
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Indeed, as others have already said. 76.2mm is equal to 3", while 127mm is equal to 5".
Old naval cannons (XIX century) were not described by its size, but by their weight, so usually a cannon was described as a 300 pounds, 250 pounds, 25 pounds, 17 pounds. As result the cannon was designed to fit a bullet weight.
That's why old cannons defined the ammunition, and the ammunition forced the size of future barrels.

Santiago
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  • With smoothbore artillery, guns that fired solid shot were described in terms of the weight of the shot (e.g. 12-pdr, 18-pdr, etc). However, shell firing artillery, such as howitzers and mortars, were described in terms of the diameter of the bore since the actual weight of the shells could vary depending on the payload. – Steve Bird Jul 04 '17 at 21:23
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I want to add another issue to the previous answers, the relation of volume to diameter.

All other things being equal, when a shell is scaled up 1.5% from 128mm to 130mm, volume goes up 4.7% if the length is changed in proportion. The shell is 1.5% wider, 1.5% higher, 1.5% longer.

Often old tanks were upgunned with larger guns rather than introducing new tank guns together with new tanks (see the KwK 40 on the Panzer IV). Old tank turrets got crowded, and finding room for larger guns and larger ammo was difficult. Sure, we're talking about just five percent, but that adds up.

o.m.
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  • @PieterGeerkens (130/128)^3 = 1.0476..., so 4.7% is good -- it could alternately be rounded to 4.8%. Yes, a 1.5% increase in each dimension would lead to a 4.56% increase in volume, but that requires rounding before the calculation is finished. – Charles Jul 05 '17 at 02:17