Getting path of project or layer file in PyQGIS

Question

I am generating new raster files from vector layers on a project. I would like to save them in the same directory as the project or layer files.

How do I find this path using PyQGIS?

score 27 · Accepted Answer · edited Jul 08 '23 at 10:06

27

For Python console:

QgsProject.instance().readPath("./") # also try "../"

Or with

dir(QgsProject.instance())

you find something like

fileName()

For Python plugin (not tested!):

from PyQt4.QtGui import QMessageBox
from qgis.core import QgsProject
path_absolute = QgsProject.instance().readPath("./")
QMessageBox.information(None, "Title", "AP: " + unicode(path_absolute))

edited Jul 08 '23 at 10:06

Taras

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answered Sep 30 '12 at 13:12

qräbnö

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9

score 21 · Answer 2 · answered Jan 17 '15 at 17:17

21

To access a vector file path, on a active layer, this code works well in Python Console:

>>>import os
>>>myfilepath= iface.activeLayer().dataProvider().dataSourceUri()
>>>myfilepath
u'/home/zeito/tiznados_canoa.tif'
>>>(myDirectory,nameFile) = os.path.split(myfilepath)
>>>myDirectory
u'/home/zeito'
>>>nameFile
u'tiznados_canoa.tif'

It was tested with my 'tiznados_canoa.tif' raster as a active layer.

answered Jan 17 '15 at 17:17

xunilk

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6

Be aware in case of vector layer the path after file name contains also pipe and layer id (C:/shapes/test.shp|layerid=0). I use path = path [:path.rfind('|')] to remove it. – Miro Nov 09 '16 at 05:24

score 13 · Answer 3 · edited Jul 08 '23 at 10:04

In QGIS 3.2 and above:

Project path:

QgsProject.instance().fileName() 
# OR
QgsProject.instance().absoluteFilePath() # C:/test/sample_project.qgz

Project folder path:

QgsProject.instance().homePath()
# OR
QgsProject.instance().absolutePath()   # C:/test

In QGIS 2.x, 3.0 and 3.1:

Project path:

QgsProject.instance().fileName()  # C:/test/sample_project.qgs

Project folder path:

QgsProject.instance().homePath() # C:/test

score 8 · Answer 4 · answered Oct 05 '12 at 13:10

8

If you want to access a vector file path, on a active layer, this seems to work:

myfilepath= os.path.dirname( unicode( qgis.utils.iface.activeLayer().dataProvider().dataSourceUri() ) ) ;
fic = myfilepath + "[% "FILE" %]"

then to open a picture or text located in same directory as mylayer:

from PyQt4 import QtWebKit, QtCore ; vue=QtWebKit.QWebView() vue.setUrl( QtCore.QUrl( fic ) ) ; vue.show()

answered Oct 05 '12 at 13:10

rha

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Useful answer but what about the file name? You use "[% "FILE" %]" but I don't understand what does it means... – G M Aug 19 '13 at 20:59

score 6 · Answer 5 · edited Jul 08 '23 at 10:05

6

I did test this on QGIS 3.4:

QgsProject.instance().fileName()

will return the entire path to the file

'C:/MyDirectory/18809_US66.qgz'

edited Jul 08 '23 at 10:05

Taras

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answered Dec 17 '18 at 20:40

Cary H

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Getting path of project or layer file in PyQGIS

5 Answers5

In QGIS 3.2 and above:

In QGIS 2.x, 3.0 and 3.1:

Linked

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