Since ArcGIS 10 comes with the ArcPy package, I'm wondering it is possible to use ArcPy functions to get Symbology (i.e color, width...) of a layer?
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For ArcGIS 10.0, if you can make use of a read-only approach, the following code sample reveals the field (and joined table) that forms the basis for the symbology of a layer. It exports a temporary msd(a zip containing xml files) and loads the specific attributes into an object. These classes might be extended to gain access to additional layer attributes.
import zipfile
from arcpy import mapping
import os
from xml.dom.minidom import parse
class LayerExtras(object):
""" An object to hold attributes loaded from xml inside the msd."""
name = ""
symbologyFieldName = ""
class MxdExtras(dict):
""" Exposes extra MXD details by raiding an exported msd
Treat this object as a dictionary with layer name as the key and a custom object
with desired attributes as the value.
You must have write access to MXD directory (creates temporary msd file).
Only layers in the first dataframe are accessed.
"""
LYR_NAME_NODE = "Name"
LYR_SYMBOL_NODE = "Symbolizer"
LYR_FIELD_NODE = "Field"
MSD_SUFFIX = "_MxdExtrasTemp.msd"
MXD_SUFFIX = ".mxd"
EXCLUDED_FILE_NAMES = ["DocumentInfo.xml", "layers/layers.xml"]
mxdPath = ""
def __init__(self, mxdPath):
self.loadMxdPath(mxdPath)
def loadMxdPath(self, mxdPath):
""" Load mxd from file path """
self.mxdPath = mxdPath.lower()
mxd = mapping.MapDocument(self.mxdPath)
msdPath = self.mxdPath.replace(self.MXD_SUFFIX, self.MSD_SUFFIX)
# Delete temporary msd if it exists
if os.path.exists(msdPath):
os.remove(msdPath)
mapping.ConvertToMSD(mxd,msdPath)
zz = zipfile.ZipFile(msdPath)
for fileName in (fileName for fileName in zz.namelist() if not fileName in self.EXCLUDED_FILE_NAMES):
dom = parse(zz.open(fileName))
name, lyr = self.loadMsdLayerDom(dom)
self[name] = lyr
del zz
os.remove(msdPath)
def loadMsdLayerDom(self, dom):
""" Load dom created from xml file inside the msd. """
lyr = LayerExtras()
# Layer name
lyr.name = dom.getElementsByTagName(self.LYR_NAME_NODE)[0].childNodes[0].nodeValue
# Symbology field name
symbologyElement = dom.getElementsByTagName(self.LYR_SYMBOL_NODE)[0]
lyr.symbologyFieldName = symbologyElement.getElementsByTagName(self.LYR_FIELD_NODE)[0].childNodes[0].nodeValue
return lyr.name, lyr
############
# Test
if __name__ == "__main__":
mxdPath = r"c:\temp\AmphibianSpeciesRichnessAverageOf30mCells.mxd"
mxde = MxdExtras(mxdPath)
for lyr in mxde.itervalues():
print "Layer Name: ", lyr.name
print "Layer Symbology Field Name: ", lyr.symbologyFieldName
print
Example output of test:
Layer Name: Amphibian Species Richness Average of 30m Cells
Layer Symbology Field Name: biodiversity.AmphAve
Michael Jackson
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ArcPy looks to let you change the symbology, but only with existing .lyr files, and not specify the symbols directly in your code based on my reading of the module.
scw
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In ArcGIS 10.1 and newer there is direct access to the symbology via the symbology property of the layer object.
For ArcGIS 10.0 the mentioned workarounds did work for me.
matt wilkie
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Bernd
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unfortunately, the symbology of a layer is read-only (according to the fifth instance of "symbology" on this page, as well as the one you cited). – Roland Apr 01 '14 at 15:30
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1However "Not all layer symbology class types are supported; for those that are not, the keyword OTHER is returned.". Unsupported types include Raster Unique Values, Unique Values Many Fields, and Dot Density. This is still true in ArcGIS 10.5. If you're lucky enough to have a supported SymbologyType see script in https://gis.stackexchange.com/questions/184133/accessing-layer-properties-with-arcpy – matt wilkie Aug 23 '17 at 22:52
with zipfile.ZipFile(msdPath) as zz:. – jpmc26 Apr 24 '18 at 01:58lyr.symbologyFieldName = symbologyElement.getElementsByTagName(self.LYR_FIELD_NODE)[0].childNodes[0].nodeValueline, sayyinglist index out of range. this is because thesymbologyElement.getElementsByTagName(self.LYR_FIELD_NODE)is empty. But why is it empty? I assumed that this is an alternative to the lyr.symbology method, but it still doesn't work. – panda Aug 30 '18 at 07:26