Does a selfdestruct affect child contracts?

Question

Say, I create a smart contract A and this contract creates another smart contract B. If I call selfdestruct on A, will this affect in any way contract B? Or can I still call functions on B after A is killed?

I found this example on Etherscan:

Original contract A: https://etherscan.io/address/0x14fea711dca8fcea6be47e14ea1406384f18c7cc
Contract B created by A: https://etherscan.io/address/0x02820e4bee488c40f7455fdca53125565148708f

Contract A is selfdestructed and therefore has no code anymore. B also has empty code, but it does not have the red SelfDestruct label on Etherscan. So did the SelfDestruct of A lead to a deletion of B's code or is this just coincidence and this contract B never had any code associated with it at all?

score 4 · Answer 1 · answered Sep 10 '18 at 15:52

4

No. selfdestruct of a contract does not effect any contracts created by the contract to be destroyed.

answered Sep 10 '18 at 15:52

Rob Hitchens

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Thanks, do you have a source or maybe even a concrete example where this is the case? – hefeleal Sep 10 '18 at 16:50

Does a selfdestruct affect child contracts?

1 Answers1