Not sure why keccak hashing of encodePacked address and bytes not equal

Question

        address addr1 = 0x70997970C51812dc3A010C7d01b50e0d17dc79C8;
        bytes memory addr2 = "0x70997970C51812dc3A010C7d01b50e0d17dc79C8";
        require(keccak256(abi.encodePacked(addr1)) == keccak256(addr2), 'not equal');

I would think that the above require statement evaluates to true, but it evaluates to false. Any reasoning as to why would be very helpful, thank you!

score 0 · Accepted Answer · answered Dec 15 '21 at 02:53

0

The result of abi.encodePacked(addr1) is a 20 bytes array.

On the other hand addr2 is a 42 bytes array.

answered Dec 15 '21 at 02:53

Ismael

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Is there any way to make addr2 20 bytes? – basketball9 Dec 15 '21 at 02:59
@basketball9 You could use something like this https://ethereum.stackexchange.com/a/40247. – Ismael Dec 15 '21 at 03:06

Not sure why keccak hashing of encodePacked address and bytes not equal

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