Function arguments in quoted lists

Question

First example:

(defun first (a)
    '(a 1))
(first 2) => (a 1)

Second example:

(defun second (b)
    (+ b 1))
(second 1) => 2

How can I get (2 1) with (first 2)?

I strongly recommend reading this Q&A regarding the dangers of your initial approach: https://emacs.stackexchange.com/q/20535 — phils, Apr 23 '17 at 10:53

score 0 · Accepted Answer · answered Apr 23 '17 at 10:08

0

Code:

(defun first (a)
    (list a 1))
(first 2)

Result:

(2 1)

answered Apr 23 '17 at 10:08

Valeriy

1 Answers1