I'm creating my own merge functions in the compositor, but I've run into a bit of a wall. How do you calculate the square root with nodes? Would one have to write a python node to do this? If so, what would that look like?
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root(x, n)==x^(1/n). So if you wanted, you could construct a node group which divides 1 by the root before feeding it to a power node, and then you'd have a root node. – gandalf3 Dec 18 '16 at 20:47