If I am understanding your question correctly, yes you can. You could consider incorporating a log or logit link function, i.e.
$$\text{exp}\Big( \text{log}\{\hat{p}\}\pm z_{\alpha/2}\Big[\sqrt{\hat{p}(1-\hat{p})/n}\Big]/\hat{p}\Big)$$
$$\text{or}$$
$$\text{logit}^{-1}\Big( \text{log}\Big\{\frac{\hat{p}}{1-\hat{p}}\Big\}\pm z_{\alpha/2}\Big[\sqrt{\hat{p}(1-\hat{p})/n}\Big]/[\hat{p}(1-\hat{p})]\Big).$$
The log link function is useful if your estimates are near 0 and your sample size is small. The logit link function is useful if your estimates are near 0 or near 1 and your sample size is small. Your estimate of $20/60=0.33$ is not close to zero by most standards, but the link functions may still help to improve the coverage of the confidence interval. For your estimate of $0.33$ they will shorten the lower confidence limit and lengthen the upper limit relative to a Wald interval using an identity link. Here log refers to the natural log with base $e$.
|
|
| Wald with identity link |
(0.21, 0.45) |
| Wald with log link |
(0.23, 0.48) |
| Wald with logit link |
(0.23, 0.46) |
With your sample size all of the intervals look similar.
If, for example, you had witnessed 3 events in a sample of size 30 then the confidence limits would be
|
|
| Wald with identity link |
(-0.01, 0.21) |
| Wald with log link |
(0.03, 0.29) |
| Wald with logit link |
(0.03, 0.27) |
Of course we would never report a negative proportion so the lower limit using the identity link would be truncated to 0 (not inclusive).