Remove object from a list of objects in python

Question

In Python, how can I remove an object from array of objects? Like this:

x = object()
y = object()
array = [x,y]
# Remove x

I've tried array.remove() but it only works with a value, not a specific location in the array. I need to be able to delete the object by addressing its position(remove array[0])

possible duplicate of [How to delete element from list in Python?](http://stackoverflow.com/questions/2056341/how-to-delete-element-from-list-in-python) — Acorn, Mar 17 '12 at 23:38

Ricardo Murillo · Answer 1 · 2014-12-16T22:26:30.273

87

In python there are no arrays, lists are used instead. There are various ways to delete an object from a list:

my_list = [1,2,4,6,7]

del my_list[1] # Removes index 1 from the list
print my_list # [1,4,6,7]
my_list.remove(4) # Removes the integer 4 from the list, not the index 4
print my_list # [1,6,7]
my_list.pop(2) # Removes index 2 from the list

In your case the appropriate method to use is pop, because it takes the index to be removed:

x = object()
y = object()
array = [x, y]
array.pop(0)
# Using the del statement
del array[0]

edited Dec 16 '14 at 22:26

answered Mar 18 '12 at 03:35

Ricardo Murillo

2,677
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1

You should update the second part of your answer and have him use .pop(0) since he specifically asks about removing by position. – redreinard Dec 15 '14 at 21:02
When using `del array[0]` is removed` from the list but `x` itself still exists. Is there a method to remove `x` simultaneously (for example by deleting `x` by its pointer)? – Sajjad Mar 13 '20 at 08:44

score 8 · Answer 2 · answered Mar 17 '12 at 23:53

8

del array[0]

where 0 is the index of the object in the list (there is no array in python)

answered Mar 17 '12 at 23:53

MattoTodd

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Muhammad Ammar Fauzan · Answer 3 · 2018-03-16T23:18:29.040

6

If you want to remove multiple object from a list. There are various ways to delete an object from a list

Try this code. a is list with all object, b is list object you want to remove.

example :

a = [1,2,3,4,5,6]
b = [2,3]

for i in b:
   if i in a:
      a.remove(i)

print(a)

the output is [1,4,5,6] I hope, it will work for you

edited Mar 16 '18 at 23:18

answered Mar 11 '18 at 11:07

Muhammad Ammar Fauzan

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What is `link` ? – Rafael Mar 11 '18 at 11:11
And `else: pass` is redundant. – Rafael Mar 11 '18 at 11:11
1

@Rafael i'm sorry, variable "link" in there is my mistake. I just to correct it. check = i in a. – Muhammad Ammar Fauzan Mar 11 '18 at 12:03
yes, no problem using else: pass or no. Thank you for your idea. @Rafael – Muhammad Ammar Fauzan Mar 11 '18 at 12:06

score 4 · Answer 4 · answered Mar 06 '19 at 03:41

You could try this to dynamically remove an object from an array without looping through it? Where e and t are just random objects.

>>> e = {'b':1, 'w': 2}
>>> t = {'b':1, 'w': 3}
>>> p = [e,t]
>>> p
[{'b': 1, 'w': 2}, {'b': 1, 'w': 3}]
>>>
>>> p.pop(p.index({'b':1, 'w': 3}))
{'b': 1, 'w': 3}
>>> p
[{'b': 1, 'w': 2}]
>>>

score 2 · Answer 5 · answered Mar 29 '20 at 16:32

2

You can remove a string from an array like this:

array = ["Bob", "Same"]
array.remove("Bob")

answered Mar 29 '20 at 16:32

Lil.Yeeet

39
2

score 1 · Answer 6 · answered May 05 '14 at 17:46

1

If you know the array location you can can pass it into itself. If you are removing multiple items I suggest you remove them in reverse order.

#Setup array
array = [55,126,555,2,36]
#Remove 55 which is in position 0
array.remove(array[0])

answered May 05 '14 at 17:46

ZeroInputCtrl

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score 0 · Answer 7 · answered Apr 30 '13 at 22:31

0

if you wanna remove the last one just do your_list.pop(-1) if you wanna remove the first one your_list.pop(0) or any index you wish to remove

answered Apr 30 '13 at 22:31

AngelloMaggio

474
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Remove object from a list of objects in python

7 Answers7

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