When should I use single quotes and double quotes in C or C++ programming?
14 Answers
In C and in C++ single quotes identify a single character, while double quotes create a string literal. 'a' is a single a character literal, while "a" is a string literal containing an 'a' and a null terminator (that is a 2 char array).
In C++ the type of a character literal is char, but note that in C, the type of a character literal is int, that is sizeof 'a' is 4 in an architecture where ints are 32bit (and CHAR_BIT is 8), while sizeof(char) is 1 everywhere.
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Some compilers also implement an extension, that allows multi-character constants. The C99 standard says:
6.4.4.4p10: "The value of an integer character constant containing more than one character (e.g., 'ab'), or containing a character or escape sequence that does not map to a single-byte execution character, is implementation-defined."
This could look like this, for instance:
const uint32_t png_ihdr = 'IHDR';
The resulting constant (in GCC, which implements this) has the value you get by taking each character and shifting it up, so that 'I' ends up in the most significant bits of the 32-bit value. Obviously, you shouldn't rely on this if you are writing platform independent code.
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8Thanks, I just saw this in some code and my response can only be described as "WTF". I have been using GCC on and off for 15 years and have never once run into this until now. – eeeeaaii Nov 14 '12 at 04:22
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+1 besides magic headers, often used for command line evaluation. – Wolf Jun 04 '14 at 10:22
Single quotes are characters (char), double quotes are null-terminated strings (char *).
char c = 'x';
char *s = "Hello World";
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@CodeGuru You use a * when the variable is a pointer type. In this case, 's' points to an array of characters. – Eiko Oct 02 '15 at 09:56
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1@OldSchool **In C++, yes, but in C, no. In C, it's a `char *`, not a `const char *`.** – Jack Murrow Dec 20 '20 at 21:26
'x'is an integer, representing the numerical value of the letter x in the machine’s character set"x"is an array of characters, two characters long, consisting of‘x’followed by‘\0’
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I was poking around stuff like: int cc = 'cc'; It happens that it's basically a byte-wise copy to an integer. Hence the way to look at it is that 'cc' which is basically 2 c's are copied to lower 2 bytes of the integer cc. If you are looking for a trivia, then
printf("%d %d", 'c', 'cc'); would give:
99 25443
that's because 25443 = 99 + 256*99
So 'cc' is a multi-character constant and not a string.
Cheers
Single quotes are for a single character. Double quotes are for a string (array of characters). You can use single quotes to build up a string one character at a time, if you like.
char myChar = 'A';
char myString[] = "Hello Mum";
char myOtherString[] = { 'H','e','l','l','o','\0' };
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single quoteis forcharacter;double quoteis forstring.
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In C, single-quotes such as 'a' indicate character constants whereas "a" is an array of characters, always terminated with the \0 character
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Double quotes are for string literals, e.g.:
char str[] = "Hello world";
Single quotes are for single character literals, e.g.:
char c = 'x';
EDIT As David stated in another answer, the type of a character literal is int.
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thanks . means character is 1 byte with no null character '/0'at the end .. string contains null character at the end . – Vishwanath Dalvi Sep 10 '10 at 09:51
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2@mr_eclair: A string *literal* always contains an implicit null terminator, but be careful. You could write something like `char str[] = {'H','e','l','l','o'};`, and `str` would *not* have a null terminator. – Oliver Charlesworth Sep 10 '10 at 10:01
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in that situation, `str` isn't a string (at least, not a C-style string, which is defined to be a NTBS). – Steve Jessop Sep 10 '10 at 16:13
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@Steve: Understood. My point to @mr_eclair was that not everything that's a `char[]` (which people often thing of as "strings") is null-terminated. – Oliver Charlesworth Sep 10 '10 at 17:27
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1@OliCharlesworth this is - fortunately - not the full truth: these are *two* string literals separated by a comment: `"hello" /*seamlessly connected to*/ "world"`. And this can make sense for commented multi-line messages. – Wolf Jun 04 '14 at 10:32
A single quote is used for character, while double quotes are used for strings.
For example...
printf("%c \n",'a');
printf("%s","Hello World");
Output
a
Hello World
If you used these in vice versa case and used a single quote for string and double quotes for a character, this will be the result:
printf("%c \n","a");
printf("%s",'Hello World');
output :
For the first line. You will get a garbage value or unexpected value or you may get an output like this:
�
While for the second statement, you will see nothing. One more thing, if you have more statements after this, they will also give you no result.
Note: PHP language gives you the flexibility to use single and double-quotes easily.
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Single quotes are denoting a char, double denote a string.
In Java, it is also the same.
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4This doesn't really add any value to the question, since this information has already been encompassed in the other answers. – Mike Precup Aug 05 '14 at 02:05
Use single quote with single char as:
char ch = 'a';
here 'a' is a char constant and is equal to the ASCII value of char a.
Use double quote with strings as:
char str[] = "foo";
here "foo" is a string literal.
Its okay to use "a" but its not okay to use 'foo'
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While I'm sure this doesn't answer what the original asker asked, in case you end up here looking for single quote in literal integers like I have...
C++14 added the ability to add single quotes (') in the middle of number literals to add some visual grouping to the numbers.
constexpr int oneBillion = 1'000'000'000;
constexpr int binary = 0b1010'0101;
constexpr int hex = 0x12'34'5678;
constexpr double pi = 3.1415926535'8979323846'2643383279'5028841971'6939937510;
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In C & C++ single quotes is known as a character ('a') whereas double quotes is know as a string ("Hello"). The difference is that a character can store anything but only one alphabet/number etc. A string can store anything. But also remember that there is a difference between '1' and 1. If you type cout<<'1'<<endl<<1; The output would be the same, but not in this case:
cout<<int('1')<<endl<<int(1);
This time the first line would be 48. As when you convert a character to an int it converts to its ascii and the ascii for '1' is 48. Same, if you do:
string s="Hi";
s+=48; //This will add "1" to the string
s+="1"; This will also add "1" to the string
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