Where to create parametrized ViewModel?

Question

I have recently parametrized my ViewModel's contructor. Before that, I was doing this in my window:

<Window.DataContext>
    <vm:MyViewModel />
</Window.DataContext>

The framework instantiated the ViewModel for me.

I know I can set DataContext in code but I would prefer a XAML way so designer can display my test data when designing.

Is this possible?

score 23 · Accepted Answer · answered Aug 03 '10 at 22:17

Use an ObjectDataProvider if you want to specify constructor parameters:

<Window.DataContext>
    <ObjectDataProvider ObjectType="vm:MyViewModel"
        xmlns:sys="clr-namespace:System;assembly=mscorlib">
        <ObjectDataProvider.ConstructorParameters>
            <sys:String>A string parameter</sys:String>
            <sys:Int32>42</sys:Int32>
        </ObjectDataProvider.ConstructorParameters>
    </ObjectDataProvider>
</Window.DataContext>

If parameter is class type? – Ashish-BeJovial Aug 20 '18 at 08:50 — Ashish-BeJovial, Aug 20 '18 at 08:50

score 13 · Answer 2 · answered Aug 03 '10 at 21:05

13

I have no idea how to pass a contructor-parameter, I think it can't be done (but it would be nice if someone proved me wrong).

What you can do is set properties on your ViewModel, as in

<Window.DataContext>
    <vm:MyViewModel  MyProperty="Hello" />
</Window.DataContext>

answered Aug 03 '10 at 21:05

Henk Holterman

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If parameter is a custom class type, than how will write in xaml? – Ashish-BeJovial Aug 20 '18 at 08:52

Where to create parametrized ViewModel?

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