Upload file via sftp with python

Question

I wrote a simple code to upload a file to a sftp server in python. I am using python 2.7

import pysftp

srv = pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log")

srv.cd('public') #chdir to public
srv.put('C:\Users\XXX\Dropbox\test.txt') #upload file to nodejs/

# Closes the connection
srv.close()

The file did not appear on the server. However, no error message appeared. What is wrong with the code?

EDIT: I have enabled logging. I discovered that the file is uploaded to the root folder and not under public folder. Seems like srv.cd('public') did not work.

It's a bit hard to tell from your description. Set `log='/tmp/pysftp.log'` when creating the Connection and investigate the log file. — Frederick Nord, Nov 17 '15 at 08:09

score 39 · Accepted Answer · answered Nov 17 '15 at 08:53

39

I found the answer to my own question.

import pysftp

srv = pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log")

with srv.cd('public'): #chdir to public
    srv.put('C:\Users\XXX\Dropbox\test.txt') #upload file to nodejs/

# Closes the connection
srv.close()

Put the srv.put inside with srv.cd

answered Nov 17 '15 at 08:53

guagay_wk

23,870
50
164
275

`ImportError: No module named pysftp` - I am using CentOS. How do i get pysftp without crashing my existing python2.7? – May 16 '18 at 09:32
@YumYumYum it means you need to download the module – Led Feb 27 '19 at 17:31
1

@YumYumYum `pip install pysftp` – alvaro nortes Apr 03 '19 at 10:17
2

Why do you need to close the connection once you passed the `with` statement ? Is it not closed already ? – Leogout Feb 14 '22 at 13:33

score 8 · Answer 2 · edited Feb 06 '21 at 04:02

import pysftp

with pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log") as sftp:

  sftp.cwd('/root/public')  # The full path
  sftp.put('C:\Users\XXX\Dropbox\test.txt')  # Upload the file

No sftp.close() is needed, because the connection is closed automatically at the end of the with-block

I did a minor change with cd to cwd

Syntax -

# sftp.put('/my/local/filename')  # upload file to public/ on remote
# sftp.get('remote_file')         # get a remote file

score 0 · Answer 3 · answered Nov 11 '21 at 21:49

0

With as a context manager will close the connection. Explicitly using srv.close() is not required

answered Nov 11 '21 at 21:49

Ambesh

51
7

Upload file via sftp with python

3 Answers3

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