I have some object.ID-s which I try to store in the user session as tuple. When I add first one it works but tuple looks like (u'2',) but when I try to add new one using mytuple = mytuple + new.id got error can only concatenate tuple (not "unicode") to tuple.
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You need to make the second element a 1-tuple, eg:
a = ('2',)
b = 'z'
new = a + (b,)
Jon Clements
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26Why you need this comma – SIslam Feb 07 '16 at 09:16
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50@SIslam Without the comma, it will just be interpreted as brackets usually used to get around the order of precedence: `(a+b)*c` – Joseph Young Feb 25 '16 at 05:54
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2yeah, but you can do `new = a + b` instead of `new = a + (b,)`. AFAICT, works the same in python3 and python2.7. – ILMostro_7 Jun 15 '18 at 11:42
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7@ILMostro_7 depends what b is though – Jon Clements Jun 15 '18 at 11:59
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2Or shortly `a += ('z',)`, as mentioned in [bellow answer](https://stackoverflow.com/a/24535123/2989289) – artu-hnrq Dec 21 '19 at 04:03
87
Since Python 3.5 (PEP 448) you can do unpacking within a tuple, list set, and dict:
a = ('2',)
b = 'z'
new = (*a, b)
nitely
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1I am trying it on Python 3.7.10, and it works with `a = ('2')`. That is without the additional comma. – nocibambi May 22 '21 at 11:42
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1@nocibambi the comma makes it a tuple, without it it's just a string. Try `a = ('23')` and `new` becomes `('2', '3', 'z')`. If you add the comma then you get `('23', 'z')`. – nitely Aug 08 '21 at 05:42
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From tuple to list to tuple :
a = ('2',)
b = 'b'
l = list(a)
l.append(b)
tuple(l)
Or with a longer list of items to append
a = ('2',)
items = ['o', 'k', 'd', 'o']
l = list(a)
for x in items:
l.append(x)
print tuple(l)
gives you
>>>
('2', 'o', 'k', 'd', 'o')
The point here is: List is a mutable sequence type. So you can change a given list by adding or removing elements. Tuple is an immutable sequence type. You can't change a tuple. So you have to create a new one.
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3However if you note to OP to convert to `list` at the beginning, append items, and then at the very end convert to `tuple` then this is the best solution +1 – jamylak May 24 '13 at 09:04
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two items including the first itemin list. but you are right, i should better add a longer=list example, see my edit – kiriloff May 24 '13 at 10:41
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Tuple can only allow adding tuple to it. The best way to do it is:
mytuple =(u'2',)
mytuple +=(new.id,)
I tried the same scenario with the below data it all seems to be working fine.
>>> mytuple = (u'2',)
>>> mytuple += ('example text',)
>>> print mytuple
(u'2','example text')
julienc
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Raul Kiran Gaddam
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12
>>> x = (u'2',)
>>> x += u"random string"
Traceback (most recent call last):
File "<pyshell#11>", line 1, in <module>
x += u"random string"
TypeError: can only concatenate tuple (not "unicode") to tuple
>>> x += (u"random string", ) # concatenate a one-tuple instead
>>> x
(u'2', u'random string')
jamylak
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7
#1 form
a = ('x', 'y')
b = a + ('z',)
print(b)
#2 form
a = ('x', 'y')
b = a + tuple('b')
print(b)
britodfbr
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2second option does not work. `TypeError: 'int' object is not iterable` – Pallav Jha Oct 10 '17 at 06:35
3
Bottom line, the easiest way to append to a tuple is to enclose the element being added with parentheses and a comma.
t = ('a', 4, 'string')
t = t + (5.0,)
print(t)
out: ('a', 4, 'string', 5.0)
alphahmed
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