I want to find a way to get all the sub-elements of an element tree like the way ElementTree.getchildren() does, since getchildren() is deprecated since Python version 2.7.
I don't want to use it anymore, though I can still use it currently.
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5 Answers
24
All sub-elements (descendants) of elem:
all_descendants = list(elem.iter())
A more complete example:
>>> import xml.etree.ElementTree as ET
>>> a = ET.Element('a')
>>> b = ET.SubElement(a, 'b')
>>> c = ET.SubElement(a, 'c')
>>> d = ET.SubElement(a, 'd')
>>> e = ET.SubElement(b, 'e')
>>> f = ET.SubElement(d, 'f')
>>> g = ET.SubElement(d, 'g')
>>> [elem.tag for elem in a.iter()]
['a', 'b', 'e', 'c', 'd', 'f', 'g']
To exclude the root itself:
>>> [elem.tag for elem in a.iter() if elem is not a]
['b', 'e', 'c', 'd', 'f', 'g']
Eli Bendersky
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1Sorry Eli, but maybe I didn't make myself understood, I just want to get all the sub-elements, not also the root. i.e. the root is unwanted here. but I think your method also contains the root object, right? – j5shi May 02 '12 at 07:04
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2But what if there are more than one sturct with tag 'a' nested in element 'a' and I want to get all sub-elements of all 'a' structs? – j5shi May 02 '12 at 07:17
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The element objects are iterable also without using the `iter()`. The element behaves also like a list; so, you can also index the subelements. – pepr May 02 '12 at 07:20
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1@pepr: yes, but that only gives you the element's immediate children, not all descendants – Eli Bendersky May 02 '12 at 07:23
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1@Eli Bendersky: I see. But the `getchildren()` also returns only the immediate children. The old equivalent of the new `list(elem.iter())` is the `list(elem.getiterator())`. It depends what Steven really wants. – pepr May 02 '12 at 11:24
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in the pydoc it is mentioned to use list() method over the node to get child elements.
list(elem)
Harshal Zope
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If you want to get all elements 'a', you can use:
a_lst = list(elem.iter('a'))
If the elem is also 'a', it will be included.
pepr
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None of the existing answers will find all children. This solution uses BeautifulSoup instead of ETree, but will find all children, instead of just top-level:
from bs4 import BeautifulSoup
with open(filename) as f:
soup = BeautifulSoup(f, 'xml')
results = soup.find_all('element_name')
Turtles Are Cute
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Maybe this does not correspond to OP actual question but in a greater sense I would suggest that if someone want to get all elements named with a certain name e.g. 'object' can use (an alternative approach to @Turtles Are Cute which to me at least seems more natural):
objs = tree.findall('object')
which also returns a list.
Neuron - Freedom for Ukraine
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Eypros
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